在Safari中打开WKWebview target ="_ blank"链接

Question

我试图让使用斯威夫特和WKWebviews打开,有一个链接我的混合iOS应用程序target="_blank",或者如果URL中包含http://,https://或mailto:在移动Safari浏览器.

从这个答案我得到这个代码.

func webView(webView: WKWebView!, createWebViewWithConfiguration     configuration: WKWebViewConfiguration!, forNavigationAction navigationAction:     WKNavigationAction!, windowFeatures: WKWindowFeatures!) -> WKWebView! {
    if navigationAction.targetFrame == nil {
        webView.loadRequest(navigationAction.request)
    }
    return nil
}

首先,这对我没有任何作用.其次,我希望它在新窗口中打开.我发现这个代码应该做那样的事情......

if let requestUrl = NSURL(string: "http://www.iSecurityPlus.com") {
     UIApplication.sharedApplication().openURL(requestUrl)
}

我如何把这两个放在一起让它们起作用？我需要添加什么来使ViewController声明工作？

Answer 1

在(从这里)

 override func loadView() {
    super.loadView()
    self.webView.navigationDelegate = self 
    self.webView.UIDelegate = self  //must have this
 }

然后添加功能(从这里,添加)...

func webView(webView: WKWebView,
    createWebViewWithConfiguration configuration: WKWebViewConfiguration,
    forNavigationAction navigationAction: WKNavigationAction,
    windowFeatures: WKWindowFeatures) -> WKWebView? {
        if navigationAction.targetFrame == nil {
            var url = navigationAction.request.URL
            if url.description.lowercaseString.rangeOfString("http://") != nil || url.description.lowercaseString.rangeOfString("https://") != nil || url.description.lowercaseString.rangeOfString("mailto:") != nil  {
                UIApplication.sharedApplication().openURL(url)
            }
        }
        return nil
}

Answer 2

首先添加WKNavigationDelegate和webviewWk.navigationDelegate = self

func webView(webView: WKWebView, decidePolicyForNavigationAction navigationAction: WKNavigationAction, decisionHandler: (WKNavigationActionPolicy) -> Void) {

        //this is a 'new window action' (aka target="_blank") > open this URL externally. If we´re doing nothing here, WKWebView will also just do nothing. Maybe this will change in a later stage of the iOS 8 Beta
        if navigationAction.navigationType == WKNavigationType.LinkActivated {
            println("here link Activated!!!")
            let url = navigationAction.request.URL
            let shared = UIApplication.sharedApplication()

            let urlString = url!.absoluteString

            if shared.canOpenURL(url!) {
                shared.openURL(url!)
            }

            decisionHandler(WKNavigationActionPolicy.Cancel)
        }

        decisionHandler(WKNavigationActionPolicy.Allow)
    }

Answer 3

针对iOS 10 Swift 3更新的代码:

override func loadView() {
    super.loadView()
    self.webView.navigationDelegate = self 
    self.webView.uiDelegate = self  //must have this
}

func webView(_ webView: WKWebView,
               createWebViewWith configuration: WKWebViewConfiguration,
               for navigationAction: WKNavigationAction,
               windowFeatures: WKWindowFeatures) -> WKWebView? {
    if navigationAction.targetFrame == nil, let url = navigationAction.request.url {
      if url.description.lowercased().range(of: "http://") != nil ||
        url.description.lowercased().range(of: "https://") != nil ||
        url.description.lowercased().range(of: "mailto:") != nil {
        UIApplication.shared.openURL(url)
      }
    }
  return nil
}