rak*_*kke 1 python dictionary numpy
我有一本字典词典,即dict[key1][key2]
应该返回一个数字.如果我这样做key2 in dict[key1]
返回True
,但dict[key1].get(key2)
返回None
.
我想这里有一些非常基本的东西,但是我被卡住了.
由于key1是a string
,而key2是a numpy.datetime64
.
编辑:
key type: <type 'numpy.datetime64'>
key: 2014-08-11T02:00:00.000000+0200
Dict: {numpy.datetime64('2014-08-11T02:00:00.000000000+0200'): 1}
key in dict.keys() True
dict.items(): [(numpy.datetime64('2014-08-11T02:00:00.000000000+0200'), 1)]
dict.get(key): None
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编辑2:
由编辑3取代
编辑3(替换编辑2):
码:
vessel = df['Vessel'].iloc[0]
print "vessel:",vessel
ati = np.datetime64(df['ATI'].iloc[0])
print "ati type:",type(ati),"value:",ati
print "Self.sailing[vessel]:",self.sailing[vessel]
print "key in dict.keys():",ati in self.sailing[vessel].keys()
sailing = self.sailing[vessel].get(ati)
print "sailing:", sailing
print "dict[key]:",self.sailing[vessel][ati]
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输出:
vessel: VESSEL2
ati type: <type 'numpy.datetime64'> value: 2014-07-21T02:00:00.000000+0200
Self.sailing[vessel]: {numpy.datetime64('2014-07-21T02:00:00.000000000+0200'): 1}
key in dict.keys(): True
sailing: None
dict[key]:
Traceback (most recent call last):
File "C:/dev/python/bmw_vpc/src/vpc_data_extractor.py", line 9, in <module>
data.create_master_file()
File "C:\dev\python\bmw_vpc\src\process.py", line 112, in create_master_file
print "dict[key]:",self.sailing[vessel][ati]
KeyError: numpy.datetime64('2014-07-21T02:00:00.000000+0200')
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编辑4:
码:
for key in self.sailing[vessel].keys():
print "Vessel:",vessel,"ati:",ati,"ati == key:",ati == key
sailing = self.sailing[vessel].get(ati)
print "Vessel:",vessel,"sailing:", sailing
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输出:
Vessel: VESSEL2 ati: 2014-07-21T02:00:00.000000+0200 ati == key: True
Vessel: VESSEL2 sailing: None
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编辑5:
感谢@ jamylak的回答,我使用Timestamp而不是datetime64-object进行了解决方法.
您提供的信息中唯一的选项是key2
存在于dict[key1]
且key2
具有值None
编辑:
它们是两个完全不同的对象,恰好看起来像完全相同的对象.
从您的代码中有:
numpy.datetime64('2014-07-21T02:00:00.000000+0200')
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和
numpy.datetime64('2014-07-21T02:00:00.000000000+0200')
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>>> (hash(numpy.datetime64('2014-07-21T02:00:00.000000000+0200'))
== hash(numpy.datetime64('2014-07-21T02:00:00.000000+0200')))
False
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这是因为当你检查in dict.keys()
它时,它对由方法构建的==
每个元素执行了相等的check()list
.keys()
numpy.datetime64('2014-07-21T02:00:00.000000000+0200') == numpy.datetime64('2014-07-21T02:00:00.000000+0200')
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如果您尝试运行key in dict
,它将返回,False
因为它不会构建中介list
而是使用hash
它们是字典的不同对象,因为它hash
是字典使用的,这就是为什么in dict.keys()
不起作用.
.get
也没有找到它,因为它返回None
,你可以将默认值更改None
为其他东西来证明这一点.
至于他们比较平等和有不同的原因hash
,我认为是某种错误.