来自HTTP的XML解析文件

Tra*_*vis 14 java xml

我有一个XML文件位于如下的位置

http://example.com/test.xml
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我正在尝试解析XML文件以在我的程序中使用它与xPath这样但它不起作用.

Document doc = builder.parse(new File(url));
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我怎样才能获得XML文件?

Fav*_*ius 21

尝试使用URLConnection.getInputStream()获取XML文件的句柄.

请参阅下面的代码,我试图打开一个xml文件并打印所有description字段:

import java.io.InputStream;
import java.net.URL;
import java.net.URLConnection;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;
import org.w3c.dom.NodeList;

public class HTTPXMLTest
{
    public static void main(String[] args) 
    {
        try {
            new HTTPXMLTest().start();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    private void start() throws Exception
    {
        URL url = new URL("http://localhost:8080/AutoLogin/resource/web.xml");
        URLConnection connection = url.openConnection();

        Document doc = parseXML(connection.getInputStream());
        NodeList descNodes = doc.getElementsByTagName("description");

        for(int i=0; i<descNodes.getLength();i++)
        {
            System.out.println(descNodes.item(i).getTextContent());
        }
    }

    private Document parseXML(InputStream stream)
    throws Exception
    {
        DocumentBuilderFactory objDocumentBuilderFactory = null;
        DocumentBuilder objDocumentBuilder = null;
        Document doc = null;
        try
        {
            objDocumentBuilderFactory = DocumentBuilderFactory.newInstance();
            objDocumentBuilder = objDocumentBuilderFactory.newDocumentBuilder();

            doc = objDocumentBuilder.parse(stream);
        }
        catch(Exception ex)
        {
            throw ex;
        }       

        return doc;
    }
}
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laz*_*laz 1

摆脱new File()

Document doc = builder.parse(url);
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