mas*_*y88 1 java templates scala view playframework
我Person在PlayFramework2.2.6中循环scala视图的集合.
Person类是超类的类User,Contact.
循环时我想访问为类扩展类指定的一些参数,比如类中的email属性User.
这是模型的类:
public class Person {
int id;
String name;
Date date;
}
public class User extends Person {
String email;
String login;
String password;
}
public class Contact extends Person {
Address address;
}
public class Customer {
List<Person> persons;
// AND NOW I WOULD LIKE TO DO THIS IN SCALA TEMPLATE
public void print() {
for(Person person: this.persons) {
if(person instanceof User) {}
System.out.println(((User)person).email);
}
}
}
Run Code Online (Sandbox Code Playgroud)
视图层:
@for(person <- persons) {
@if(person instanceOf User) {
@((User)person).email
}
}
Run Code Online (Sandbox Code Playgroud)
但我收到一个错误:
value instanceOf is not a member of models.Person
Run Code Online (Sandbox Code Playgroud)
请给我一些帮助:
在PlayFramework的Scala模板/视图层中.谢谢.
Scala/Twirl的等价物应该是:
要验证实例类型:
person.isInstanceOf[User] // bool?
Run Code Online (Sandbox Code Playgroud)
施法:
person.asInstanceOf[User] // User instance
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
796 次 |
| 最近记录: |