Rob*_*wen 25 django serialization python-3.x django-rest-framework
如果我有一个嵌套的序列化程序:
class ChildSerializer(ModelSerializer):
class Meta:
fields = ('c_name', )
model = Child
class ParentSerializer(ModelSerializer):
child = ChildSerializer(many=True, read_only=True)
class Meta:
model = Parent
fields = ('p_name', 'child')
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我想访问嵌套序列化器中的上下文,我该怎么做?据我所知,上下文没有传递给孩子.
我希望能够在字段上为每个用户实现一个权限模型,因为我重写了ModelSerializer的get_fields()方法:
def get_fields(self):
fields = super().get_fields()
....
for f in fields:
if has_rights(self.context['request'].user, f, "read"):
ret_val[f] = fields[f]
....
return ret_val
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这适用于常规序列化程序,但是当嵌套子项传递给get_fields()时,上下文以及请求和用户不可用.串行器嵌套时如何访问上下文?
Rob*_*wen 20
好的,我找到了一个有效的解 我用ParentizerMethodField替换了Parent类中的ChildSerializer赋值,后者添加了上下文.然后将其传递给CustomModelSerializer中的get_fields方法:
class ChildSerializer(CustomModelSerializer):
class Meta:
fields = ('c_name', )
model = Child
class ParentSerializer(CustomModelSerializer):
child = serializers.SerializerMethodField('get_child_serializer')
class Meta:
model = Parent
fields = ('p_name', 'child')
def get_child_serializer(self, obj):
serializer_context = {'request': self.context.get('request') }
children = Child.objects.all().filter(parent=obj)
serializer = ChildSerializer(children, many=True, context=serializer_context)
return serializer.data
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在我的CustomModelSerializer中:
class CustomModelSerializer(rest_serializer_classes.HyperlinkedModelSerializer):
def __init__(self, *args, **kwargs):
"""
Make sure a user is coupled to the serializer (needed for permissions)
"""
super().__init__(*args, **kwargs)
if not self.context:
self._context = getattr(self.Meta, 'context', {})
try:
self.user = self.context['request'].user
except KeyError:
self.user = None
def get_fields(self):
ret = OrderedDict()
if not self.user:
print("No user associated with object")
return ret
fields = super().get_fields()
# Bypass permission if superuser
if self.user.is_superuser:
return fields
for f in fields:
if has_right(self.user, self.Meta.model.__name__.lower(), f, "read"):
ret[f] = fields[f]
return ret
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这似乎工作正常,当我撤销Child.c_name或Parent.child上的读取权限时,在序列化程序中丢弃子字段
Tim*_*ion 10
如果您不能改变子序列化程序的性质,如@Kirill Cherepanov 和@Robin van Leeuwen 的回答,一个简单但不是完全集成的解决方案是在__init__()
函数中手动传递上下文:
class ChildSerializer(CustomModelSerializer):
class Meta:
fields = ('c_name', )
model = Child
class ParentSerializer(CustomModelSerializer):
child = ChildSerializer(many=True, read_only=True)
class Meta:
model = Parent
fields = ('p_name', 'child')
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
# We pass the "upper serializer" context to the "nested one"
self.fields['child'].context.update(self.context)
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好的,我找到了一个最终的解决方案,它将完全按照要求进行操作 - 将上下文传递给嵌套序列化器。要实现这一目标,需要重写to_representation(self, instance)
嵌套序列化器,因此它看起来像:
def to_representation(self, instance):
# here we update current serializer's context (access it as self._context)
# to access parent's context we use parent.context
# if there is no parent than it's the first serializer in the chain and it doesn't need any context except for itself's
# for example (after all the checks)
self._context["request"] = self.parent.context["request"]
# and that is it! The modified context will be used for serialization as if it was passed as usually
return super().to_representation(instance)
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你可以serialziers.ListField
改用。ListField
自动将上下文传递给它的孩子。所以,这是你的代码
class ChildSerializer(ModelSerializer):
class Meta:
fields = ('c_name', )
model = Child
class ParentSerializer(ModelSerializer):
child = serializers.ListField(read_only=True, child=ChildSerializer())
class Meta:
model = Parent
fields = ('p_name', 'child')
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