用一对一关系序列化对象Django

use*_*423 3 python django rest serialization django-rest-framework

我是django的新手。我正在研究Rest API。我有一个可选的“是”关系,即学生是雇员。我试图序列化这两个模型,以便得到组合的json结果。请让我知道是否有人可以帮助我。谢谢

class Employee(models.Model):
    full_name=models.CharField(max_length=100,blank=True)
    email_id=models.EmailField(max_length=100,blank=True)
    mobile_no=models.CharField(max_length=11,blank=True)
    is_job_ready=models.BooleanField(False)
    type=models.CharField(max_length=20,blank=True)
    location_preference=models.CharField(max_length=20,blank=True)

class Student(models.Model):
    college=models.CharField(max_length=100)
    year=models.CharField(max_length=20)
    is_with_college=models.BooleanField()
    employee=models.OneToOneField(Employee,primary_key=True)
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met*_*mza 5

Django的REST框架具有序列化嵌套对象中一些很好的工具。

您需要他们所谓的嵌套关系。像这样 -

from rest_framework import serializers

# define your models here ...

class EmployeeSerializer(serializers.ModelSerializer):
  class Meta:
    model = Employee
    fields = ('full_name', 'email_id', 'mobile_no', 'is_job_ready', 'type', 'location_preference')

class StudentSerializer(serializers.ModelSerializer):
  employee = EmployeeSerializer(read_only = True)

  class Meta:
    model = Student
    fields = ('college', 'year', 'is_with_college', 'employee')
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然后,您可以加载序列化程序并使用类似以下的内容-

from myapp.models import StudentSerializer

student = Student.objects.first()
serializer = StudentSerializer(student)

serializer.data
# { 'college': 'Naropa University',
#    'is_with_college': True,
#    'year': '2015'}
#    'employee': {
#      'full_name' : 'Chogyam Trungpa',
#      'email_id' : 'teacher@naropa.edu',
#      'mobile_no' : '555-555-5555',
#      'is_job_ready' : True,
#      'type' :'Teacher',
#      'location_preference' : 'Boulder, CO'
#    }
#  }
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  • @KishanMehta http://www.django-rest-framework.org/api-guide/relations/#writable-nested-serializers (2认同)