获取重复的数组输出 - java

Question

有人可以善良并帮助我在这里.提前致谢...

我的代码在下面输出字符串作为重复.我不想使用Sets或ArrayList.我正在使用java.util.Random.我正在尝试编写一个代码来检查字符串是否已经被随机输出,如果是,那么它将不会显示.我哪里出错了,我该如何解决这个问题.

public class Worldcountries
{

    private static Random nums = new Random();   

    private static String[] countries =
    {
        "America", "Candada", "Chile", "Argentina"
    };


    public static int Dice()
    { 
        return (generator.nums.nextInt(6) + 1);  
    } 


    public String randomCounties()
    {
        String aTemp = " ";
        int numOfTimes = Dice();
        int dup = 0;

        for(int i=0 ; i<numOfTimes; i++)
        {
            // I think it's in the if statement where I am going wrong. 
            if (!countries[i].equals(countries[i])) 
            {
                i = i + 1;
            }
            else
            {
                dup--;  
            }

            // and maybe here  
            aTemp = aTemp + countries[nums.nextInt(countries.length)];
            aTemp = aTemp + ",";  
        }

        return aTemp;
    }
}

所以我得到(随机)的输出是"美国,美国,智利"应该是"美国,智利".

Answer 1

你什么时候认为这是假的？

countries[i].equals(countries[i])

编辑:

这是一个骨架解决方案.我将为您填写辅助方法.

public String[] countries;

public boolean contains(String[] arr, String value) {
    //return true if value is already in arr, false otherwise
}

public String chooseRandomCountry() {
   //chooses a random country from countries
}

//...
int diceRoll = rollDice();
String[] selection = new String[diceRoll];
for ( int i = 0; i < selection.length; i++ ) {
    while (true) {
       String randomCountry = chooseRandomCountry();
       if ( !contains(selection, randomCountry ) {   
          selection[i] = randomCountry;
          break;
       }
    }
}

//...then build the string here

这不会检查重要的事情,比如唯一的数量countries.