python wave模块可以接受StringIO对象吗

Question

我正在尝试使用wave模块来读取python中的wav文件。

我的应用程序不常见的是我没有使用文件或文件名来读取wav文件，而是将wav文件放在缓冲区中。

这就是我在做什么

import StringIO

buffer = StringIO.StringIO()
buffer.output(wav_buffer)

file = wave.open(buffer, 'r')

但是我EOFError运行它时得到了...

  File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/wave.py", line 493, in open
return Wave_read(f)
File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/wave.py", line 163, in __init__
self.initfp(f)
File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/wave.py", line 128, in initfp
self._file = Chunk(file, bigendian = 0)
File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/chunk.py", line 63, in __init__
raise EOFError

我知道这些StringIO东西可以用于创建wav文件，并且我尝试了以下操作，并且效果很好

import StringIO


buffer = StringIO.StringIO()
audio_out = wave.open(buffer, 'w')
audio_out.setframerate(m.getRate())
audio_out.setsampwidth(2)
audio_out.setcomptype('NONE', 'not compressed')
audio_out.setnchannels(1)

audio_out.writeframes(raw_audio)
audio_out.close()
buffer.flush()

# these lines do not work...
# buffer.output(wav_buffer)
# file = wave.open(buffer, 'r')

# this file plays out fine in VLC
file = open(FILE_NAME + ".wav", 'w')
file.write(buffer.getvalue())
file.close()
buffer.close()

Answer 1

尝试这个：

import StringIO

buffer = StringIO.StringIO(wav_buffer)
file = wave.open(buffer, 'r')