列表中的Postgres JSON查询

jan*_*son 2 postgresql json

我在匹配表中有以下数据:

{"Id":1,"Teams":[{"Name":"TeamA","Players":[{"Name":"AAA"},{"Name":"BBB"}]},{"Name":"TeamB","Players":[{"Name":"CCC"},{"Name":"DDD"}]}],"TeamRank":[1,2]}

{"Id":2,"Teams":[{"Name":"TeamA","Players":[{"Name":"CCC"},{"Name":"BBB"}]},{"Name":"TeamB","Players":[{"Name":"AAA"},{"Name":"DDD"}]}],"TeamRank":[1,2]}
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最终,我想获得一份独特的团队名单.

以下问题我一直在尝试使用以下方法访问Team Name属性:

SELECT json_array_elements(match->>'Teams') FROM matches
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这回来了

ERROR: function json_array_elements(text) does not exist
SQL state: 42883
Hint: No function matches the given name and argument types. You might need to add explicit type casts.
Character: 1560
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我也试过json_array_elements(match - >>'Teams':: json)和json_array_elements(to_json(match - >>'Teams'))无济于事.

但是以下查询

SELECT match->>'Teams' FROM matches;
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返回

"[{"Name":"TeamA","Players":[{"Name":"AAA"},{"Name":"BBB"}]},{"Name":"TeamB","Players":[{"Name":"CCC"},{"Name":"DDD"}]}]"
"[{"Name":"TeamA","Players":[{"Name":"CCC"},{"Name":"BBB"}]},{"Name":"TeamB","Players":[{"Name":"AAA"},{"Name":"DDD"}]}]"
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Kri*_*ján 8

->>运营商给你的结果text,但你希望它保持json.使用->它给你的json价值.

参考:http://www.postgresql.org/docs/9.4/static/functions-json.html

我相信操作上的顺序json_array_elements(match->>'Teams'::json)转换Teamsjson它运行之前->>.json_array_elements((match->>'Teams')::json)应该工作,但只是一个迂回版本->.

to_json(match->>'Teams')转换为text然后将该文本作为json对象提供给您.它没有解析text回来json.