在SQL中减去上一行减去当前行

Question

我有一张桌子orders.

如何减去列的上一行减去当前行 Incoming

有人可以帮忙吗

Answer 1

在我的SQL中

 select a.Incoming, 
coalesce(a.Incoming - 
    (select b.Incoming from orders b where b.id = a.id + 1), a.Incoming) as differance
from orders a

Answer 2

LAG在Oracle中使用函数.

试试这个查询

SELECT DATE_IN,Incoming,
   LAG(Incoming, 1, 0) OVER (ORDER BY Incoming) AS inc_previous,
   LAG(Incoming, 1, 0) OVER (ORDER BY Incoming) - Incoming AS Diff
FROM orders

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