将带有数据AND文件的JSON发布到Web Api - jQuery/MVC

Rob*_*ott 30 c# ajax asp.net-mvc jquery json

我需要用一个请求发送到带有JSON(最好)的Api控制器.

问题是传递数据和文件(图像上传).我的财产空了(null).

我看了很多博客,但似乎无法通过图像传递数据.

public class SomeModel
{
    public string Name { get; set; }
    public string Email { get; set; }
    public string City { get; set; }
    public HttpPostedFileBase Image { get; set; }
    public string Title { get; set; }
    public string Description { get; set; }
    public string CountryCode { get; set; }
}


    [HttpPost]
    public void CreateContestEntry(SomeModel model)
    {
        // model.Image is always null
        // .. get image here - the other properties no issues
    }
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jQuery的

    // create model for controller
    var model = {
        Name: $.trim($contestForm.find('[name="nombre"]').val()) + ' ' + $.trim($contestForm.find('[name="apellido"]').val()),
        Email: $.trim($contestForm.find('[name="email"]').val().toLowerCase()),
        City: $.trim($contestForm.find('[name="cuidad"]').val()),
        Title: $.trim($contestForm.find('[name="title"]').val()),
        Description: $.trim($contestForm.find('[name="description"]').val()),
        CountryCode: 'co',
        Image: $contestForm.find('[name="file-es"]')[0].files[0]  // this has the file for sure
    };

    $.ajax({
        url: '/Umbraco/api/ControllerName/CreateContestEntry',
        type: 'POST',
        dataType: 'json',
        data: JSON.stringify(model),
        //data: $('#test-form').serialize(),  // tried this and using FormData()
        processData: false,
        async: false,
        contentType: 'application/json; charset=utf-8',
        complete: function (data) {

        },
        error: function (response) {
            console.log(response.responseText);
        }
    });
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在此输入图像描述

我看过的博客:


当我尝试FormData$('#form1').serialize()接近时,我的provider.FileData并且provider.FormData总是也是空的.我model从方法中删除了参数,当我打开它时断点正在击中.

    [HttpPost]
    public void CreateContestEntry()
    {
        string root = HttpContext.Current.Server.MapPath("~/App_Data");
        var provider = new MultipartFormDataStreamProvider(root);

        try
        {
            // Read the form data.
            Request.Content.ReadAsMultipartAsync(provider);

            // This illustrates how to get the file names.
            foreach (MultipartFileData file in provider.FileData)
            {
                // empty
            }

            foreach (var key in provider.FormData.AllKeys)
            {
                foreach (var val in provider.FormData.GetValues(key))
                {
                    // empty
                }
            }
            //return Request.CreateResponse(HttpStatusCode.OK);
        }
        catch(Exception ex)
        {

        }
    }
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解:

关于@Musa的回答,这是Api控制器代码.我将NameValueCollection映射到我的模型.

    [HttpPost]
    public void CreateContestEntry()
    {
        try
        {
            // get variables first
            NameValueCollection nvc = HttpContext.Current.Request.Form;
            var model = new WAR2015ContestModel();

            // iterate through and map to strongly typed model
            foreach (string kvp in nvc.AllKeys)
            {
                PropertyInfo pi = model.GetType().GetProperty(kvp, BindingFlags.Public | BindingFlags.Instance);
                if (pi != null)
                {
                    pi.SetValue(model, nvc[kvp], null);
                }
            }

            model.Image = HttpContext.Current.Request.Files["Image"];
        }
        catch(Exception ex)
        {

        }
    }
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Mus*_*usa 22

您无法使用JSON上传文件(即任意二进制数据),因为JSON是文本格式.你将不得不使用多部分表单数据.

// create model for controller
var model = new FormData();
model.append('Name', $.trim($contestForm.find('[name="nombre"]').val()) + ' ' + $.trim($contestForm.find('[name="apellido"]').val()));
model.append('Email', $.trim($contestForm.find('[name="email"]').val().toLowerCase()));
model.append('City', $.trim($contestForm.find('[name="cuidad"]').val()));
model.append('Title', $.trim($contestForm.find('[name="title"]').val()));
model.append('Description', $.trim($contestForm.find('[name="description"]').val()));
model.append('CountryCode', 'co');
model.append('Image', $contestForm.find('[name="file-es"]')[0].files[0]);  // this has the file for sure

$.ajax({
    url: '/Umbraco/api/ControllerName/CreateContestEntry',
    type: 'POST',
    dataType: 'json',
    data: model,
    processData: false,
    contentType: false,// not json
    complete: function (data) {
        var mediaId = $.parseJSON(data.responseText); //?

    },
    error: function (response) {
        console.log(response.responseText);
    }
});
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