C中的递归结构定义,错误"前向声明"

Question

我想将我的结构声明为递归结构.所以我到现在为止做的是这样的:

 typedef struct {

 char *string;
 struct my_struct **children; //I want a list of children, therefore pointer to pointer
 int child_num;
 } my_struct;

但是当我尝试像这样初始化它时:

my_struct *alig;
alig = malloc(sizeof(my_struct)*1);
alig->child_num = 5;
alig->string = malloc(sizeof(char)*9);
strncpy(alig->string, "AAACGTCA", 8);

alig->children = malloc(sizeof(my_struct*)*alig->child_num);

int j;
for (j = 0; j < alig->child_num; j++) {
    alig->children[j] = malloc(sizeof(my_struct)*1);
    alig->children[j]->string = malloc(sizeof(char)*9); // *********error ********
}

我收到错误:"./ structurs.h:27:13:注意:'struct my_struct'的前向声明"

以及标记行处的此错误:main.c:56:22:错误:类型'struct my_struct'的定义不完整

有谁现在我的错误是??

Answer 1

struct my_struct你的代码中没有,你struct是匿名的typedef,你需要它是这样的

typedef struct my_struct {
     char *string;
     struct my_struct **children;
     int child_num;
} my_struct;

甚至

typedef struct my_struct my_struct;
struct my_struct {
     char *string;
     my_struct **children;
     int child_num;
};