Symfony2/Doctrine中的两列上的Query Builder和Group By生成重复项

Edd*_*ddy 17 php symfony doctrine-orm

我正在创建一个消息包,其中消息按联系人分组.在我的索引页面上,我显示不同的线程.当您在一个线程上进行clic时,它会显示您和您的联系人之间交换的所有消息.我使用查询生成器在索引页面上显示线程:

$qb = $this->createQueryBuilder('m')
    ->where('m.from = ?1 or m.to = ?1')
    ->groupBy('m.to, m.from')
    ->orderBy('m.date', 'DESC')
    ->setParameter(1, $user->getId())
    ->setMaxResults($pagination) // limit
    ->setFirstResult($pagination * $page) // offset
;
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如果我有3个条目,例如:

+----+------+----+
| id | from | to |
+----+------+----+
| 1  | 1    | 2  |
+----+------+----+
| 2  | 2    | 1  |
+----+------+----+
| 3  | 1    | 2  |
+----+------+----+
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我预计:

+----+------+----+
| id | from | to |
+----+------+----+
| 3  | 1    | 2  |
+----+------+----+
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但我得到:

+----+------+----+
| id | from | to |
+----+------+----+
| 2  | 2    | 1  |
+----+------+----+
| 3  | 1    | 2  |
+----+------+----+
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我找到了一种使用SQL的方法,使用from_id和to_id的相同别名:

SELECT id, from_id as c, to_id as c FROM Message WHERE c = 1 GROUP BY from_id, to_id
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但我不知道如何用Doctrine做到这一点.

编辑:

直到我得到一个更好的主意,我使用一个键轻松"分组".

// entity

/**
* @ORM\Column(name="key", type="string", length=40)
*/
private $key;

/**
 * @ORM\PrePersist()
 */
public function setOnPrePersist()
{
    if($this->from < $this->to) {
        $key = $this->from . 't' . $this->to;
    } else {
        $key = $this->to . 't' . $this->from;
    }

    $this->key = $key;
}

// query builder

$qb = $this->createQueryBuilder('m')
    ->where('m.from = ?1 or m.to = ?1')
    ->groupBy('m.key')
    ->orderBy('m.date', 'DESC')
    ->setParameter(1, $user->getId())
    ->setMaxResults($pagination) // limit
    ->setFirstResult($pagination * $page) // offset
;

return $qb->getQuery()->getResult();
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小智 7

如果“分组依据”中有许多列,则必须使用addGroupBy()方法。

$qb = $this->createQueryBuilder('m')
    ->where('m.from = ?1 or m.to = ?1')
    ->groupBy('m.to')
    ->addGroupBy('m.from')
    ->orderBy('m.date', 'DESC')
    ->setParameter(1, $user->getId())
    ->setMaxResults($pagination) // limit
    ->setFirstResult($pagination * $page) // offset
;
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:)


Cha*_*ari 0

使用学说 DQL 方法尝试以下操作 -

$query = $em->createQuery("SELECT m.id, m.from_id as c, m.to_id as c FROM AcmeDemoBunlde:Message as m WHERE m.c = 1 GROUP BY m.from_id, m.to_id"); 

$messageDetails = $query->getResult(); 
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替换为您适当的包名称,而不是AcmeDemoBundle 。