XSL:如何在for-each中打印迭代节点

Question

XML:

<skills>
  <skill>PHP</skill>
  <skill>CSS</skill>
  <skill>HTML</skill>
  <skill>XML</skill>
</skills>

XSL:

<ul>
  <xsl:for-each select="skills/skill">
    <li><xsl:value-of select="[what should be xpath here]" /></li
  </xsl:for-each>
</ul>

这里打印每项技能的xpath应该是什么？

Answer 1

您可以按如下方式获取技能标签的值:

<xsl:for-each select="skills/skill">
<li><xsl:value-of select="." /></li>
</xsl:for-each>