R2D*_*2D2 3 php mysql mysqli function fetchall
我有一个代码,当我在页面上使用它时,但我试图使这个功能.我无法让它工作,似乎变量$ customer和$ system没有被发送到代码.即使我在Raw中键入它.有什么想法错了吗?$ Customer是客户的名称,$ system可以是'Source'或'Target'.
function status_total($customer, $system){
$sql_customer = "SELECT * FROM `Customer` WHERE Cust_Name = '$customer' LIMIT 0,1";
$customer_selection = mysqli_query($conn,$sql_customer);
$customer_row = mysqli_fetch_assoc($customer_selection);
$env_lines = $customer_row["Env_Lines"];
$cust_id = $customer_row["Cust_ID"];
$sql_last_records = "SELECT * FROM $system WHERE Cust_ID = $cust_id ORDER BY Time DESC LIMIT $env_lines";
$record_selection = mysqli_query($conn, $sql_last_records);
$result = mysqli_fetch_all($record_selection, MYSQLI_ASSOC);
$states = array_column($result, "Stat");
if($states == array_fill(0, count($states), "Run")) {
echo "Success";
} else
echo "Fail";
}
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代码的问题是$conn变量,它被视为函数内的局部变量.你应该:
function status_total($customer, $system){
global $conn;
$sql_customer = "SELECT * FROM `Customer` WHERE Cust_Name = '$customer' LIMIT 0,1";
$customer_selection = mysqli_query($conn,$sql_customer);
$customer_row = mysqli_fetch_assoc($customer_selection);
$env_lines = $customer_row["Env_Lines"];
$cust_id = $customer_row["Cust_ID"];
$sql_last_records = "SELECT * FROM $system WHERE Cust_ID = $cust_id ORDER BY Time DESC LIMIT $env_lines";
$record_selection = mysqli_query($conn, $sql_last_records);
$result = mysqli_fetch_all($record_selection, MYSQLI_ASSOC);
$states = array_column($result, "Stat");
if($states == array_fill(0, count($states), "Run")) {
echo "Success";
} else
echo "Fail";
}
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或者你也可以传递$conn函数,所以将函数的定义更改为:
function status_total($conn, $customer, $system){...}
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