python中的语法错误:

Question

我正在学习python.它在此脚本中提供语法错误.我无法弄明白.

import exceptions
class FOUND(Exception): pass

x = [1,2,3,4,56,73,29,35,12,32,63,12,76,75,89]


while True:

    try:
        test = int(raw_input('Enter integer to be checked in list:'))
        count = -1
        for y in x:
            count += 1
            if y == test:
                raise FOUND
    except ValueError as e:
        print "Not a valid integer (%s)"%(e)
    except FOUND:
        print "Found (%d) at (%d)"%(test,count)
    else:
        print "Not found ,Appending (%d) to list at location (%d)"%(test,count+1)
        x.append(test)
    finally:
        print "The List:"
        print x
        print " "

语法无效,并突出显示此行中的结束双引号: print "Not a valid integer (%s)"%(e)

Answer 1

print没有括号是来自python 2,如果你使用python 3,你需要使用print().

您不能将异常格式化为%d- %d是整数.