如何禁用特定URL的弹簧安全性

Pra*_*ngh 65 java spring spring-mvc spring-security

我正在使用无状态弹簧安全性,但在注册的情况下我想禁用spring security.I禁用使用

antMatchers("/api/v1/signup").permitAll().
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但它不起作用,我收到以下错误:

 message=An Authentication object was not found in the SecurityContext, type=org.springframework.security.authentication.AuthenticationCredentialsNotFoundException
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我认为这意味着Spring安全过滤器正在运行

我的网址顺序总是"/ api/v1"

我的春天配置是

@Override
    protected void configure(HttpSecurity http) throws Exception {

         http.
         csrf().disable().
         sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS).
         and().
         authorizeRequests().
         antMatchers("/api/v1/signup").permitAll().
         anyRequest().authenticated().
         and().
         anonymous().disable();
        http.addFilterBefore(new AuthenticationFilter(authenticationManager()), BasicAuthenticationFilter.class);
    }
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我的验证过滤器是

@Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        HttpServletRequest httpRequest = asHttp(request);
        HttpServletResponse httpResponse = asHttp(response);

        String username = httpRequest.getHeader("X-Auth-Username");
        String password = httpRequest.getHeader("X-Auth-Password");
        String token = httpRequest.getHeader("X-Auth-Token");

        String resourcePath = new UrlPathHelper().getPathWithinApplication(httpRequest);

        try {

            if (postToAuthenticate(httpRequest, resourcePath)) {            
                processUsernamePasswordAuthentication(httpResponse, username, password);
                return;
            }

            if(token != null){
                processTokenAuthentication(token);
            }
            chain.doFilter(request, response);
        } catch (InternalAuthenticationServiceException internalAuthenticationServiceException) {
            SecurityContextHolder.clearContext();
            logger.error("Internal authentication service exception", internalAuthenticationServiceException);
            httpResponse.sendError(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
        } catch (AuthenticationException authenticationException) {
            SecurityContextHolder.clearContext();
            httpResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED, authenticationException.getMessage());
        } finally {
        }
    }

     private HttpServletRequest asHttp(ServletRequest request) {
            return (HttpServletRequest) request;
        }

        private HttpServletResponse asHttp(ServletResponse response) {
            return (HttpServletResponse) response;
        }

        private boolean postToAuthenticate(HttpServletRequest httpRequest, String resourcePath) {
            return Constant.AUTHENTICATE_URL.equalsIgnoreCase(resourcePath) && httpRequest.getMethod().equals("POST");
        }

        private void processUsernamePasswordAuthentication(HttpServletResponse httpResponse,String username, String password) throws IOException {
            Authentication resultOfAuthentication = tryToAuthenticateWithUsernameAndPassword(username, password);
            SecurityContextHolder.getContext().setAuthentication(resultOfAuthentication);
            httpResponse.setStatus(HttpServletResponse.SC_OK);
            httpResponse.addHeader("Content-Type", "application/json");
            httpResponse.addHeader("X-Auth-Token", resultOfAuthentication.getDetails().toString());
        }

        private Authentication tryToAuthenticateWithUsernameAndPassword(String username,String password) {
            UsernamePasswordAuthenticationToken requestAuthentication = new UsernamePasswordAuthenticationToken(username, password);
            return tryToAuthenticate(requestAuthentication);
        }

        private void processTokenAuthentication(String token) {
            Authentication resultOfAuthentication = tryToAuthenticateWithToken(token);
            SecurityContextHolder.getContext().setAuthentication(resultOfAuthentication);
        }

        private Authentication tryToAuthenticateWithToken(String token) {
            PreAuthenticatedAuthenticationToken requestAuthentication = new PreAuthenticatedAuthenticationToken(token, null);
            return tryToAuthenticate(requestAuthentication);
        }

        private Authentication tryToAuthenticate(Authentication requestAuthentication) {
            Authentication responseAuthentication = authenticationManager.authenticate(requestAuthentication);
            if (responseAuthentication == null || !responseAuthentication.isAuthenticated()) {
                throw new InternalAuthenticationServiceException("Unable to authenticate Domain User for provided credentials");
            }
            logger.debug("User successfully authenticated");
            return responseAuthentication;
        }
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我的控制器是

@RestController
public class UserController {

    @Autowired
    UserService userService;

    /**
     * to pass user info to service
     */
    @RequestMapping(value = "api/v1/signup",method = RequestMethod.POST)
    public String saveUser(@RequestBody User user) {
        userService.saveUser(user);
        return "User registerted successfully";
    }
}
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我对春天来说是全新的,请帮我怎么做?

M. *_*num 120

使用permitAll它时意味着每个经过身份验证的用户,但是您禁用了匿名访问,因此无法使用.

你想要的是忽略某些URL,以覆盖configure获取WebSecurity对象和ignore模式的方法.

@Override
public void configure(WebSecurity web) throws Exception {
    web.ignoring().antMatchers("/api/v1/signup");
}
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并从该HttpSecurity部分中删除该行.这将告诉Spring Security忽略此URL并且不对它们应用任何过滤器.

  • 什么文件写入? (4认同)
  • @JacobZimmerman https://spring.io/blog/2013/07/03/spring-security-java-config-preview-web-security/ Web安全类的配置器 (3认同)
  • 只是想补充一点,您必须扩展“WebSecurityConfigurerAdapter”并“覆盖”其中的此“方法”。 (2认同)

小智 13

我有一个更好的方法:

http
    .authorizeRequests()
    .antMatchers("/api/v1/signup/**").permitAll()
    .anyRequest().authenticated()
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  • 这个片段应该在哪里调用? (4认同)
  • 这是网上最常见的做法,其实这是错误的做法。如果您允许全部,则意味着它仍然需要进行身份验证,但您最终允许了它。那么为什么我们应该对注册访问进行身份验证(我的意思是身份验证过滤器仍将被触发)? (4认同)
  • @ViacheslavShalamov 在你的 `WebSecurityConfig 扩展了 WebSecurityConfigurerAdapter` 的 `configure(HttpSecurity http)` 方法中。请参阅 https://www.baeldung.com/java-config-spring-security (2认同)

小智 8

<http pattern="/resources/**" security="none"/>
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或者使用Java配置:

web.ignoring().antMatchers("/resources/**");
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而不是旧的:

 <intercept-url pattern="/resources/**" filters="none"/>
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为exp.禁用登录页面的安全性:

  <intercept-url pattern="/login*" filters="none" />
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eig*_*sha 8

正如@M.Deinum 已经写了答案。

我尝试使用 api /api/v1/signup。它将绕过过滤器/自定义过滤器,但浏览器会调用一个额外的请求/favicon.ico,因此,我也在 web.ignoring() 中添加了它,它对我有用。

@Override
public void configure(WebSecurity web) throws Exception {
    web.ignoring().antMatchers("/api/v1/signup", "/favicon.ico");
}
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对于上述问题,也许这不是必需的。


Tom*_*zyk 5

这可能不是您问题的完整答案,但是,如果您正在寻找禁用csrf保护的方法,则可以执行以下操作:

@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeRequests()
                .antMatchers("/web/admin/**").hasAnyRole(ADMIN.toString(), GUEST.toString())
                .anyRequest().permitAll()
                .and()
                .formLogin().loginPage("/web/login").permitAll()
                .and()
                .csrf().ignoringAntMatchers("/contact-email")
                .and()
                .logout().logoutUrl("/web/logout").logoutSuccessUrl("/web/").permitAll();
    }

    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        auth.inMemoryAuthentication()
                .withUser("admin").password("admin").roles(ADMIN.toString())
                .and()
                .withUser("guest").password("guest").roles(GUEST.toString());
    }

}
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我已经包含了完整的配置,但关键是:

.csrf().ignoringAntMatchers("/contact-email")
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