ato*_*3ls 4 python plot numpy matplotlib polar-coordinates
假设我有以下极坐标图:
a=-0.49+1j*1.14
plt.polar([0,angle(x)],[0,abs(x)],linewidth=5)
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我想将径向限制调整为 0 到 2。
做这个的最好方式是什么?
请注意,我是专门询问该plt.polar()方法(而不是polar=True在类似问题中常见的正常图中使用参数)。
这似乎有效,除非我从控制台(Spyder、Win7)进行绘图:
>>> ax=plt.gca()
>>> ax.set_rlim(0,2)
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您可以使用经典方法
import matplotlib.pyplot as plt
import numpy as np
x = np.arange(-180.0,190.0,10)
theta = (np.pi/180.0 )*x # in radians
offset = 2.0
R1 = [-0.358,-0.483,-0.479,-0.346,-0.121,0.137,0.358,0.483,0.479,0.346,0.121,\
-0.137,-0.358,-0.483,-0.479,-0.346,-0.121,0.137,0.358,0.483,0.479,0.346,0.121,\
-0.137,-0.358,-0.483,-0.479,-0.346,-0.121,0.137,0.358,0.483,0.479,0.346,0.121,\
-0.137,-0.358]
fig1 = plt.figure()
ax1 = fig1.add_axes([0.1,0.1,0.8,0.8],polar=True)
ax1.set_ylim(-2,2)
ax1.set_yticks(np.arange(-2,2,0.5))
ax1.plot(theta,R1,lw=2.5)
plt.show()
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