NSubstitute使用out参数模拟void方法

Question

我是NSubstitute的新手,我试图void用2个out参数模拟一个方法,我很确定我做错了.

我有一个CustomerDataAccess类具有以下签名的方法:

void GetCustomerWithAddresses(int customerId, 
                              out List<Customer> customers, 
                              out List<Address> addresses);

在CustomerRepository调用它的GetCustomer方法,然后调用CustomerDataAccess.GetCustomerWithAddressesDAL方法.然后,DAL方法out为客户输出一个参数,为地址输出一个参数.然后,存储库方法用于AutoMapper将DAL方法中的两个对象映射到存储库随后返回的业务域.

这是我到目前为止的代码,它不起作用.我的研究没有帮助我确定我需要做些什么来解决这个问题.如何设置out参数的值？

// Arange
ICustomerDataAccess customerDataAccess = Substitute.For<ICustomerDataAccess>();
IList<Customer> customers;
IList<Address> addresses;

customerDataAccess.When(x => x.GetCustomerWithAddresses(
    1, out customers, out addresses))
    .Do(x =>
    {
        customers = new List<Customer>() { new Customer() { CustomerId = 1, CustomerName = "John Doe" } };
        addresses = new List<Address>() { new Address() { AddressId = 1, AddressLine1 = "123 Main St", City = "Atlanta" } };
    });

CustomerRepository sut = new CustomerRepository(customerDataAccess);

// Act
Customer customer = sut.GetCustomer(1);

// Assert
Assert.IsNotNull(customer);

Answer 1

out使用参数位置作为索引更新参数.它在Returns NSubstitute的文档中有解释.因此,对于您的特定情况,您正在填充第二个和第三个参数,因此您应该像这样设置您的调用:

customerDataAccess.When(x => x.GetCustomerWithAddresses(1, out customers, out addresses))
.Do(x =>
{
    x[1] = new List<Customer>() { new Customer() { CustomerId = 1, CustomerName = "John Doe" } };
    x[2] = new List<Address>() { new Address() { AddressId = 1, AddressLine1 = "123 Main St", City = "Atlanta" } };
});