kat*_*n55 12 javascript php ajax jquery
我在ajax调用时遇到问题.
这是关于ajax的代码:
$('#Subjects').click(function() {
$.ajax({
type: 'POST',
url: '../portal/curriculum.php',
data: 'studentNumber='+$('#StudentID').val(),
success: function(data)
{
$('#curriculum').html(data);
}
});
});
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当我studentNumber在另一页上回音时,studentNumber是undefined.这是为什么?
小智 1
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("button").click(function(){
$.post("test1.php",
{
name: "Makemelive Technologies",
city: "Mumbai"
},
function(data,status){
alert("Data: " + data + "\nStatus: " + status);
});
});
});
</script>
</head>
<body>
<button>Send an HTTP POST request to a page and get the result back</button>
</body>
</html>
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上面将调用 test1.php ,其代码为
<?php
$fname=$_REQUEST['name'];
$city= $_REQUEST['city'];
echo "Company Name is ". $fname. " and it's located in ". $city ;
?>
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