SQLSRV查询将输出参数作为奇怪文本返回

Question

我在SQL Server 2012中有一个存储过程,它首先检查数据是否存在,如果存在,则将Output参数设置@Return为1并运行select查询,如果不存在,则设置@Return为0并返回不同的select查询.

在测试此存储过程以确保数据准确时,它是完美的并返回我期望的数据.问题在于PHP端在尝试读取它显示的输出参数??t_rrr时应该显示1或0.我相信问题可能在sqlsrv_query中的预定义常量中,但我似乎无法使其工作.这是我的代码:

PHP:

if(isset($_GET['accno'])) {

$search = $_GET['accno'];

$return = "";

$tsql_callSP = "EXEC Intranet.CustomerSearch @Search=?, @Return=?";
$params = array( 
    array($search, SQLSRV_PARAM_IN),
    array($return, SQLSRV_PARAM_OUT, SQLSRV_PHPTYPE_STRING(SQLSRV_ENC_CHAR),SQLSRV_SQLTYPE_INT),
    );

/* Execute the query. */
$stmt = sqlsrv_query( $conn, $tsql_callSP, $params);
if( $stmt === false )
{
    echo "EXEC Intranet.CustomerSearch Failed\n";
    die( print_r( sqlsrv_errors(), true));
}

while($res = sqlsrv_next_result($stmt))
{
    // make sure all result sets are stepped through, 
    // since the output params may not be set until this happens
}

echo $return;

if($return == 0) { ?>

   //1st Result Set
   while($row = sqlsrv_fetch_array($stmt)) {
   }

<?php } elseif($return == 1) { // End if Return 0 ?>

   //2nd Result Set
   while($row = sqlsrv_fetch_array($stmt)) {
   }

<?php } // End if Return 1 ?>

SQL存储过程:

USE [Intranet]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

ALTER PROCEDURE [Intranet].[CustomerSearch]
    @Search nvarchar(10)
    ,@Return int output
AS
BEGIN
    SET NOCOUNT ON;

    IF EXISTS
        (
            SELECT KeyCode
            FROM Autopart.dbo.Customer
            WHERE KeyCode = @Search
        )
    BEGIN

        SELECT
            Customer.KeyCode
            ,Customer.X13
            ,Customer.Name
            ,Customer.Addra
            ,Customer.Addrb
            ,Customer.Addrc
            ,Customer.Addrd
            ,Customer.Addre
            ,Customer.PCode
            ,Customer.CTitle
            ,Customer.Climit
            ,Customer.Ptype
            ,Customer.Stel
            ,Customer.SCont
            ,Customer.ACont
            ,Customer.XString5
            ,Customer.Locked
            ,Customer.Email
            ,Customer.StopStatus
            ,CusNotes.Comment
        FROM
            Autopart.dbo.Customer
            LEFT OUTER JOIN Autopart.dbo.CusNotes ON Autopart.dbo.Customer.KeyCode = Autopart.dbo.CusNotes.Account
        WHERE
            (Customer.KeyCode = @Search)
            AND (CusNotes.Seqno = 1 OR CusNotes.Seqno IS NULL)

        SET @Return = 1

    END ELSE BEGIN

        SELECT TOP 100
            KeyCode
            ,Name
            ,PCode
            ,Addra
            ,Addrb
            ,Addrc
        FROM
            AUTOPART.dbo.Customer
        WHERE
            (KeyCode LIKE '%'+@Search+'%'
            OR Name LIKE '%'+@Search+'%'
            OR PCode LIKE '%'+@Search+'%')

        SET @Return = 0

    END
END

我试过更改PHP和SQL类型但无法获得所需的结果.奇怪的是,如果我创建一个正确返回的存储过程INSERT或UPDATE语句OUTPUT.

编辑:

SQL Server存储过程排序规则是Latin1_General_CI_AS

Answer 1

我碰巧在我的VirtualBox上安装了SQL Server和PHP,所以我玩了.

一些事情:

• 具有适当类型值的Init参数.
• &传递参数时使用.
• 读取存储过程返回的所有结果sqlsrv_next_result.这个建议来自sqlsrv_prepare底部的例子.

这是代码:

$search = "qweryt";
$return = 123;

$tsql_callSP = "EXEC Intranet.CustomerSearch @Search=?, @Return=?";
$params = array( 
    array(&$search, SQLSRV_PARAM_IN),
    array(&$return, SQLSRV_PARAM_OUT),
    );

$stmt = sqlsrv_query($conn, $tsql_callSP, $params);
if ($stmt === false)
{
    echo "EXEC Intranet.CustomerSearch Failed\n";
    die( print_r( sqlsrv_errors(), true));
}
else
{
    while($res = sqlsrv_next_result($stmt))
    {
        // make sure all result sets are stepped through, 
        // since the output params may not be set until this happens
    }
}

echo $return;

已通过PHP 5.4.28,SQL Server Express 2014,PHP SQLSRV 3.2的Microsoft驱动程序验证

如果您的存储过程只执行INSERT或者UPDATE,即不返回结果SELECT,则sqlsrv_next_result恰好不需要获取output参数的值.如果SELECT与输出参数一起使用,则实际上意味着该过程返回多个结果集,您需要读取所有这些结果集.

实际上,这是一个非常相似的问题.

编辑

如果我理解正确,您首先要检索OUTPUT参数的值.然后,您想要检索SELECT语句的结果.

据我了解,这是不可能的.SQL Server SELECT在第一个结果集中返回语句结果,您可以使用该结果集进行读取sqlsrv_fetch_array.然后使用移动到第二个结果集sqlsrv_next_result.此时,OUTPUT参数的值将传输到PHP变量,因为SQL Server会OUTPUT在最后一个结果集中发送参数值.在您调用之后sqlsrv_next_result,第一个结果集不再可用sqlsrv_fetch_array.

顺便说一下,当你说

奇怪的是,如果我创建一个INSERT或UPDATE语句的存储过程,OUTPUT会正确返回.

,这很有道理.如果存储过程没有SELECT语句且没有语句SET NOCOUNT ON;,则返回的唯一结果集是OUTPUT参数,因此为PHP变量分配了正确的值而没有显式调用sqlsrv_next_result.

所以,你至少有两个选择.

1)使用将完整结果读SELECT入临时数组sqlsrv_fetch_array.然后使用sqlsrv_next_result获取OUTPUT参数的值.然后SELECT根据OUTPUT参数的接收值处理第一个保存在数组中的结果.

2)根本不要使用OUTPUT参数.使用此类参数,SQL Server会隐式返回多个结果集.由于您有任何方式的多个结果集,请显式返回两个结果集.在你的存储过程中,首先SELECT只返回一行一个数字,然后你的主要SELECT:

ALTER PROCEDURE [Intranet].[CustomerSearch]
    @Search nvarchar(10)
AS
BEGIN
    SET NOCOUNT ON;

    IF EXISTS
        (
            SELECT KeyCode
            FROM Autopart.dbo.Customer
            WHERE KeyCode = @Search
        )
    BEGIN
        SELECT CAST(1 AS int) AS ReturnCode;

        SELECT
            Customer.KeyCode
            ,Customer.X13
            ,Customer.Name
            ,Customer.Addra
            ,Customer.Addrb
            ,Customer.Addrc
            ,Customer.Addrd
            ,Customer.Addre
            ,Customer.PCode
            ,Customer.CTitle
            ,Customer.Climit
            ,Customer.Ptype
            ,Customer.Stel
            ,Customer.SCont
            ,Customer.ACont
            ,Customer.XString5
            ,Customer.Locked
            ,Customer.Email
            ,Customer.StopStatus
            ,CusNotes.Comment
        FROM
            Autopart.dbo.Customer
            LEFT OUTER JOIN Autopart.dbo.CusNotes ON Autopart.dbo.Customer.KeyCode = Autopart.dbo.CusNotes.Account
        WHERE
            (Customer.KeyCode = @Search)
            AND (CusNotes.Seqno = 1 OR CusNotes.Seqno IS NULL)
        ;

    END ELSE BEGIN

        SELECT CAST(0 AS int) AS ReturnCode;

        SELECT TOP 100
            KeyCode
            ,Name
            ,PCode
            ,Addra
            ,Addrb
            ,Addrc
        FROM
            AUTOPART.dbo.Customer
        WHERE
            KeyCode LIKE '%'+@Search+'%'
            OR Name LIKE '%'+@Search+'%'
            OR PCode LIKE '%'+@Search+'%'
        ;
    END
END

在PHP代码中sqlsrv_fetch_array第一次调用ReturnCode.然后调用sqlsrv_next_result切换到第二个结果集.然后调用sqlsrv_fetch_array读取主要的结果SELECT.

$search = "qweryt";

$tsql_callSP = "EXEC Intranet.CustomerSearch @ParamSearch=?";
$params = array
    (
    array(&$search, SQLSRV_PARAM_IN)
    );

$stmt = sqlsrv_query($conn, $tsql_callSP, $params);
if( $stmt === false )
{
    echo "EXEC Failed\n";
    die( print_r( sqlsrv_errors(), true));
}

echo "First result set:\n";
while ($row = sqlsrv_fetch_array($stmt))
{
    var_dump($row);
}

echo "Next result:\n";
$next_res = sqlsrv_next_result($stmt);
var_dump($next_res);

echo "Second result set:\n";
while ($row = sqlsrv_fetch_array($stmt))
{
    var_dump($row);
}