从URI旋转图像并将旋转的图像保存到同一位置

act*_*ram 2 android uri image bitmap save

我正在尝试从现有URI创建一个位图,旋转位图并将其保存到与JPEG文件相同的位置.在尝试了几个解决方案之后,这是我当前的代码:

try {
    // Get the Bitmap from the known URI. This seems to work.
    Bitmap bmp = MediaStore.Images.Media.getBitmap(this.getContentResolver(), this.currUserImgUri);

    // Rotate the Bitmap thanks to a rotated matrix. This seems to work.
    Matrix matrix = new Matrix();
    matrix.postRotate(-90);
    bmp = Bitmap.createBitmap(bmp, 0, 0, bmp.getWidth(), bmp.getHeight(), matrix, true);

    // Create an output stream which will write the Bitmap bytes to the file located at the URI path.
    File imageFile = new File(this.currUserImgUri.getPath());
    FileOutputStream fOut = new FileOutputStream(imageFile); // --> here an Exception is catched; see below.
    // The following doesn't work neither:
    // FileOutputStream fOut = new FileOutputStream(this.currUserImgUri.getPath());

    // Write the compressed file into the output stream
    bmp.compress(Bitmap.CompressFormat.JPEG, 85, fOut);
    fOut.flush();
    fOut.close();

} catch (FileNotFoundException e1) {
    e1.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}
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被捕获的例外情况如下:

java.io.FileNotFoundException:/ external/images/media/8439:open failed:ENOENT(没有这样的文件或目录)

任何人都可以向我解释如果我刚刚创建文件并且可以访问其URI,文件是否不存在?

也许我对此一切都错了?在这种情况下,根据其URI将旋转图像保存到同一位置的正确方法是什么?

mcd*_*mcd 6

嘿,你可以这样做使用将位图写入文件.

// Rotate the Bitmap thanks to a rotated matrix. This seems to work.
   Bitmap bitmap = MediaStore.Images.Media.getBitmap(getContext().getContentResolver(), photoURI);
   Matrix matrix = new Matrix();
   matrix.postRotate(90);
   Bitmap bmp = Bitmap.createBitmap(bitmap, 0, 0, bitmap.getWidth(), bitmap.getHeight(), matrix, true);
   //learn content provider for more info
   OutputStream os=getContext().getContentResolver().openOutputStream(photoURI);
   bmp.compress(Bitmap.CompressFormat.PNG,100,os);
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不要忘记刷新和关闭输出流.实际上内容提供商拥有自己的uri计划.