我有以下脚本:
<script type= 'text/javascript'>
function displayPlayer() {
var input = document.getElementById("player_stuff").elements;
var position = input[0];
var player_id = input[1];
document.getElementById('disp_player').innerHTML = position + player_id
}
</script>
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以及一个简单的 HTML 表单:
<form id = 'player_stuff' onsubmit = 'displayPlayer()'>
Player's Position:<br>
<input type="radio" name="position" value="p1" checked>Position One
<input type="radio" name="position" value="p2" checked>Position Two
<input type="radio" name="position" value="p3" checked>Position Three
<input type="radio" name="position" value="p4" checked>Positin Four
<br/>
Add by Player ID:<br>
<input type='text' name='player_id'>
<input type="submit" value="Submit Player" id='smit' >
</form>
<div id = 'roster'>
<h3>Current Roster</h3>
<p id= 'disp_player'></p>
</div>
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这个想法是,当我点击“提交球员”按钮时,它将触发displayPlayer()函数并将位置名称和球员 ID 添加到
<p id= 'disp_player'></p>标签中。
我做错了什么,因为什么也没有出现?
您可以使用 完全避免提交<button type="button">,然后可以绑定onclick的事件button。您可以通过避免使用输入列表来简化事情,而是使用querySelector:
<form id = 'player_stuff'>
Player's Position:<br>
<input type="radio" name="position" value="p1" checked>Position One
<input type="radio" name="position" value="p2">Position Two
<input type="radio" name="position" value="p3">Position Three
<input type="radio" name="position" value="p4">Positin Four
<br/>
Add by Player ID:<br>
<input type='text' name='player_id'>
<input type="button" value="Submit Player" id='smit' >
</form>
<div id="disp_player"></div>
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然后使用querySelector和querySelectorAll
document.getElementById('smit').onclick = function () {
var checkedPosition =
document.querySelectorAll("#player_stuff [name='position']:checked");
var playerId =
document.querySelector("#player_stuff [name='player_id']");
var position = checkedPosition[0].value;
var player_id = playerId.value;
document.getElementById('disp_player').innerHTML =
position + " " + player_id;
}
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请参阅此处的小提琴。
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