cou*_*011 9 c# sql asp.net ado.net
我得到例外:"具体演员无效",这里是代码
con.Open();
string insertQuery = @"Insert into Tender (Name, Name1, Name2) values ('Val1','Val2','Val3');Select Scope_Identity();";
SqlCommand cmd = new SqlCommand(insertQuery, con);
cmd.ExecuteNonQuery();
tenderId = (int)cmd.ExecuteScalar();
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Ant*_*ram 22
为了完整性,您的代码示例有三个问题.
1)您正在通过调用ExecuteNonQuery和执行两次查询ExecuteScalar.因此,每次运行此函数时,您将在表中插入两条记录.您的SQL虽然是两个不同的语句,但它们将一起运行,因此您只需要调用它ExecuteScalar.
2)Scope_Identity() 返回小数.您既可以使用Convert.ToInt32查询结果,也可以将返回值转换为decimal,然后转换为int.
3)确保将连接和命令对象包装在using语句中,以便正确处理它们.
using (SqlConnection connection = new SqlConnection(connectionString))
{
using (SqlCommand command = new SqlCommand(sql, connection))
{
connection.Open();
int tenderId = (int)(decimal)command.ExecuteScalar();
}
}
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试试这个:-
con.Open();
string insertQuery = @"Insert into Tender (Name, Name1, Name2) values ('Val1','Val2','Val3');Select Scope_Identity();";
SqlCommand cmd = new SqlCommand(insertQuery, con);
tenderId = Convert.ToInt32(cmd.ExecuteScalar());
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编辑
它应该是这样,因为正确指出scope_identity()返回一个数字(38,0): -
tenderId = Convert.ToInt32(cmd.ExecuteScalar());
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注意:您仍然需要删除: -
cmd.ExecuteNonQuery();
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