azt*_*azt 9 .net c# visual-studio
我将一个(C#)结构转换为一个类,需要经历所有类型的使用,以确保前隐式副本和现在的引用行为没有不良影响.
有没有办法找到使用/涉及这种特定类型的所有引用?
我尝试Find all References了这种类型,并获得明确说明类型名称的所有位置,这是一个良好的开端.
但是,我没有获得返回和修改此类型的实例的位置.特别是我使用返回值分配给隐含类型变量的行var,或者对先前定义的变量的所有赋值.
我可以使用任何功能或技巧吗?我想,这种结构到类转换的特殊情况经常发生.也许你有一些建议如何找到所有可能的问题?
您可以手动重命名该类...每个错误都是使用它的地方.但我认为Visual Studio将在一定数量的错误后停止.
您可以将[Obsolete]其标记为类,其所有属性及其所有方法.然后每次使用它们时都会发出警告.
请注意,[Obsolete]"技巧"有一些限制:
[Obsolete]
public class MyClass
{
}
public static void Test1(MyClass test2) // This line has a warning
{
var y = test2; // ***This line doesn't have a warning***
MyClass z = test2; // This line has a warning
}
Run Code Online (Sandbox Code Playgroud)
所以它和Find all References...一样
另一种解决方案,基于Visual Studio的FxCop/Code Analysis:
这是一个自定义规则,基于http://blogs.msdn.com/b/codeanalysis/archive/2010/03/26/how-to-write-custom-static-code-analysis-rules-and的说明-integrate了他们,成为视觉工作室,2010.aspx
程序集的默认命名空间(您可以在属性中设置)必须是MyCustomFxCopRules.平台目标是x86.
using Microsoft.FxCop.Sdk;
namespace MyCustomFxCopRules
{
public class StructAssignmentFinder : BaseIntrospectionRule
{
public StructAssignmentFinder()
: base("StructAssignmentFinder", "MyCustomFxCopRules.RuleMetadata", typeof(StructAssignmentFinder).Assembly)
{
var ms = new MyStruct();
var tt = ms;
}
public override TargetVisibilities TargetVisibility
{
get
{
return TargetVisibilities.All;
}
}
public override ProblemCollection Check(ModuleNode module)
{
Visit(module);
return Problems;
}
public override void VisitAssignmentStatement(AssignmentStatement assignment)
{
// You could even use FullName
if ((assignment.Source != null && assignment.Source.Type != null && assignment.Source.Type.Name.Name == "MyStruct") ||
(assignment.Target != null && assignment.Target.Type != null && assignment.Target.Type.Name.Name == "MyStruct"))
{
Problem problem = new Problem(GetNamedResolution("Struct", assignment.Target.Type.Name.Name), assignment);
Problems.Add(problem);
}
base.VisitAssignmentStatement(assignment);
}
public override void VisitConstruct(Construct construct)
{
Method targetMethod = (Method)((MemberBinding)construct.Constructor).BoundMember;
if (targetMethod.Parameters.Any(x => x.Type.Name.Name == "MyStruct"))
{
Problem problem = new Problem(GetNamedResolution("ParameterType", "MyStruct", targetMethod.Name.Name), construct);
Problems.Add(problem);
}
base.VisitConstruct(construct);
}
public override void VisitMethodCall(MethodCall call)
{
Method targetMethod = (Method)((MemberBinding)call.Callee).BoundMember;
if (targetMethod.ReturnType.Name.Name == "MyStruct")
{
Problem problem = new Problem(GetNamedResolution("ReturnType", targetMethod.ReturnType.Name.Name, targetMethod.Name.Name), call);
Problems.Add(problem);
}
if (targetMethod.Parameters.Any(x => x.Type.Name.Name == "MyStruct"))
{
Problem problem = new Problem(GetNamedResolution("ParameterType", "MyStruct", targetMethod.Name.Name), call);
Problems.Add(problem);
}
base.VisitMethodCall(call);
}
Run Code Online (Sandbox Code Playgroud)
在RuleMetadata.xml(它必须是一个嵌入的资源)
<?xml version="1.0" encoding="utf-8" ?>
<Rules FriendlyName="Rules about Structs">
<Rule TypeName="StructAssignmentRule" Category="MyRules" CheckId="CR1000">
<Name>Struct Assignment Finder</Name>
<Description>Struct Assignment Finder</Description>
<Url></Url>
<Resolution Name="Struct">There is an assignment of struct '{0}'.</Resolution>
<Resolution Name="ReturnType">'{0}' is the return type for a call to '{1}'.</Resolution>
<Resolution Name="ParameterType">'{0}' is a parameter type for a call to '{1}'.</Resolution>
<Email></Email>
<MessageLevel Certainty="100">Warning</MessageLevel>
<FixCategories>NonBreaking</FixCategories>
<Owner></Owner>
</Rule>
</Rules>
Run Code Online (Sandbox Code Playgroud)
基于此,很容易为其他角落情况添加其他规则,我肯定忘了:-)
我正在使用的测试文件:
public struct MyStruct
{
}
class Test
{
public Test()
{
var ms = new MyStruct();
var ms2 = ms;
ms3 = ms;
ms = ms3;
ms4 = ms;
ms = ms4;
ms4 = ms4;
new MyObject(default(MyStruct));
}
public MyStruct ms3;
public MyStruct ms4 { get; set; }
}
public class MyObject
{
public MyObject(MyStruct par1)
{
}
}
Run Code Online (Sandbox Code Playgroud)
请注意,调试规则很棘手...... FxCopCmd.exe使用Visual Studio直接调用时,调试很容易(但我认为不确定).
| 归档时间: |
|
| 查看次数: |
2724 次 |
| 最近记录: |