如何在Oracle中实现多值属性?

5 sql oracle plsql

我想在一个表的“电子邮件ID”列中存储多个“电子邮件ID”作为多值属性。我该如何在oracle中做到这一点?

APC*_*APC 3

传统的关系方式是使用子堆表:

create table emails 
    (id number
     , email_address varchar2(254)
     , constraint em_t23_fk foreign key (id)
                  references t23 (id)
                  )
/
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但是,您正在暗示嵌套表:

create type email_t as object
    (email_address varchar2(254))
/

create type email_nt as table of email_t
/
alter table t23
    add emails email_nt
    nested table emails store as emails_table
/
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它的工作原理如下:

SQL> update t23
  2  set emails = email_nt (email_t('sam_i_am@example.com')
  3                          , email_t('green_eggs_n_ham@yahoo.co.uk'))
  4  where id = 222
  5  /

1 row updated.

SQL> select * from t23
  2  where id = 222
  3  /

        ID NAME                           DOB
---------- ------------------------------ ---------
EMAILS(EMAIL_ADDRESS)
----------------------------------------------------------------------------------
       222 Sam-I-Am                       06-AUG-02
EMAIL_NT(EMAIL_T('sam_i_am@example.com'), EMAIL_T('green_eggs_n_ham@yahoo.co.uk'))


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编辑

与VARRAY的解决方案基本相同:

SQL> alter table t23
  2      drop column emails
  3  /

Table altered.

SQL> create type email_va as varray(5) of varchar2(254)
  2  /

Type created.

SQL> alter table t23
  2      add emails email_va
  3  /

Table altered.

SQL> update t23
  2  set emails = email_va ('sam_i_am@example.com'
  3                        , 'green_eggs_n_ham@yahoo.co.uk')
  4  where id = 222
  5  /

1 row updated.

SQL> select t23.name
  2         , e.*
  3  from t23
  4       , table (t23.emails) e
  5  where t23.id = 222
  6  /

NAME                           COLUMN_VALUE
------------------------------ ---------------------------------
Sam-I-Am                       sam_i_am@example.com
Sam-I-Am                       green_eggs_n_ham@yahoo.co.uk

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