Cha*_*gaD 1 windows batch-file
@echo off
For /f "tokens=2-4 delims=/ " %%a in ('date /t') do (set mydate=%%c-%%a-%%b)
For /f "tokens=1-2 delims=/:" %%a in ('time /t') do (set mytime=%%a-%%b)
set mydir="%mydate%-%mytime%"
mkdir %mydir%
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使用上面的批处理脚本,我可以创建一个目录名称,如2015-05-14-11-30 AM
现在我需要将时间转换为 24 格式并删除 AM/PM
预期的文件夹名称 - 2015-05-14-11-30
怎么做 ?
我认为你应该使用%TIME%伪变量。
这是一个例子:
@echo off
For /f "tokens=1-4 delims=/:." %%a in ("%TIME%") do (
SET HH24=%%a
SET MI=%%b
SET SS=%%c
SET FF=%%d
)
For /f "tokens=1-2 delims=/,." %%a in ("%SS%") do (
SET JUST_SS=%%a
)
echo HH24=%HH24%
echo MI=%MI%
echo SS=%SS%
echo FF=%FF%
echo JUST_SS=%JUST_SS%
echo mytime=%HH24%-%MI%-%JUST_SS%
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好吧,我意识到如果小时数小于 10,HH24 有一个空的空间,所以这里你有另一个解决方案,使用%time:
SET HH=%time:~0,2%
if "%HH:~0,1%" == " " SET HH=0%HH:~1,1%
echo HH=%HH%
SET MI=%time:~3,2%
if "%MI:~0,1%" == " " SET MI=0%MI:~1,1%
echo MI=%MI%
SET SS=%time:~6,2%
if "%SS:~0,1%" == " " SET SS=0%SS:~1,1%
echo SS=%SS%
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按照@Stephan 指出的建议(TIME变量取决于区域设置),我们可以使用这种方法:
@echo off
for /f "delims=" %%a in ('wmic OS get localdatetime ^| find "."') do set datetime=%%a
set "YYYY=%datetime:~0,4%"
set "MM=%datetime:~4,2%"
set "DD=%datetime:~6,2%"
set "HH=%datetime:~8,2%"
set "MI=%datetime:~10,2%"
set "SS=%datetime:~12,2%"
set fullstamp=%YYYY%-%MM%-%DD%-%HH%-%MI%-%SS%
echo fullstamp=%fullstamp%
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