从wget解析http响应头

Question

我试图从wget的结果中提取一条线但是遇到了麻烦.这是我的wget电话:

$ wget -SO- -T 1 -t 1 http://myurl.com:15000/myhtml.html

输出:

--18:24:12--  http://xxx.xxxx.xxxx:15000/myhtml.html
           => `-'
Resolving xxx.xxxx.xxxx... xxx.xxxx.xxxx
Connecting to xxx.xxxx.xxxx|xxx.xxxx.xxxx|:15000... connected.
HTTP request sent, awaiting response...
  HTTP/1.1 302 Found
  Date: Tue, 18 Nov 2008 23:24:12 GMT
  Server: IBM_HTTP_Server
  Expires: Thu, 01 Dec 1994 16:00:00 GMT
  Location: https://xxx.xxxx.xxxx/siteminderagent/...
  Content-Length: 508
  Keep-Alive: timeout=10, max=100
  Connection: Keep-Alive
  Content-Type: text/html; charset=iso-8859-1
Location: https://xxx.xxxx.xxxx//siteminderagent/...
--18:24:13--  https://xxx.xxxx.xxxx/siteminderagent/...
           => `-'
Resolving xxx.xxxx.xxxx... failed: Name or service not known.

如果我这样做:

$ wget -SO- -T 1 -t 1 http://myurl.com:15000/myhtml.html | egrep -i "302" <br/>

它不会返回包含字符串的行.我只想检查网站或siteminder是否已启动.

Answer 1

你正在寻找的wget的输出写在stderr上.你必须重定向它:

$ wget -SO- -T 1 -t 1 http://myurl.com:15000/myhtml.html 2>&1 | egrep -i "302" 

Answer 2

wget将标题打印到stderr,而不是标准输出.您可以将stderr重定向到stdout,如下所示:

wget -SO- -T 1 -t 1 http://myurl.com:15000/myhtml.html 2>&1 | egrep -i "302"

"2>&1"部分表示将文件描述符2(stderr)重定向('>')到文件描述符1(stdout).