MSTest有一个流畅的断言API吗？

Question

我最近接触过nUnit中的流畅界面,我喜欢它; 但是,我正在使用msTest.

有没有人知道是否有一个流畅的界面,无论是测试框架不可知还是msTest？

Answer 1

请参阅流利断言.你可以做类似的事情

"ABCDEFGHI".Should().StartWith("AB").And.EndWith("HI").And.Contain("EF").And.HaveLength(9);

new[] { 1, 2, 3 }.Should().HaveCount(4, "because we thought we put three items in the 
collection"))

dtoCollection.Should().Contain(dto => dto.Id != null);

collection.Should().HaveCount(c => c >= 3);

dto.ShouldHave().AllPropertiesBut(d => d.Id).EqualTo(customer);

dt1.Should().BeWithin(TimeSpan.FromHours(50)).Before(dt2); 

Action action = () => recipe.AddIngredient("Milk", 100, Unit.Spoon);
action
   .ShouldThrow<RuleViolationException>()
   .WithMessage("Cannot change the unit of an existing ingredient")
   .And.Violations.Should().Contain(BusinessRule.CannotChangeIngredientQuanity

Answer 2

见http://sharptestex.codeplex.com/

注意:SharpTestsEx似乎不再积极开发,推荐替代方案是http://www.fluentassertions.com/.

SharpTestsEx(Sharp Tests Extensions)是一组可扩展的扩展.主要目标是编写简短的断言,其中Visual Studio IDE intellisense是您的指南.#TestsEx可以与NUnit,MsTests,xUnit,MbUnit ...一起使用,甚至可以在Silverlight中使用.

强类型断言的语法示例(取自网页):

true.Should().Be.True();
false.Should().Be.False();

const string something = "something";
something.Should().Contain("some");
something.Should().Not.Contain("also");
something.ToUpperInvariant().Should().Not.Contain("some");

something.Should()
    .StartWith("so")
    .And
    .EndWith("ing")
    .And
    .Contain("meth");

something.Should()
    .Not.StartWith("ing")
    .And
    .Not.EndWith("so")
    .And
    .Not.Contain("body");

var ints = new[] { 1, 2, 3 };
ints.Should().Have.SameSequenceAs(new[] { 1, 2, 3 });
ints.Should().Not.Have.SameSequenceAs(new[] { 3, 2, 1 });
ints.Should().Not.Be.Null();
ints.Should().Not.Be.Empty();

ints.Should()
    .Contain(2)
    .And
    .Not.Contain(4);

(new int[0]).Should().Be.Empty();