如何获取默认情况下抛出的异常对象

Question

我知道如果我们使用'as'语法,我们可以得到异常对象: -

try:
    1/0
except ZeroDivisionError as e:
    print "can not divide zero"
    print(str(e))

我想抓住一切 ......前: -

try:
    1/0
except * as e:
    print "some error"
    print(str(e))

可以这样做吗？

Answer 1

所有Python的异常都是子类Exception,所以你想要:

try:
    1/0
except Exception as e:
    print "some error"
    print(str(e))
# Output:
some error
integer division or modulo by zero