用于动态端点的Apache CXF客户端

and*_*nka 27 java web-services cxf client-side

我现在使用Apache CXF作为.NET服务的Web服务客户端来绕过NTLM身份验证.它工作得很好,但我想知道为什么我似乎无法设置Web服务目标端点.CXF似乎在运行时希望WSDL出于某种奇怪的原因 - 不确定.它需要来自WSDL的物理端点,我认为它在测试环境中工作正常,但在部署时它肯定会改变.

这里有一些代码来演示:

        MyWebServices service = new MyWebServices ();
        MyWebServicesSoap port = service.getMyWebServicesSoap12();

        // Turn off chunking so that NTLM can occur
        Client client = ClientProxy.getClient(port);
        HTTPConduit http = (HTTPConduit) client.getConduit();
        HTTPClientPolicy httpClientPolicy = new HTTPClientPolicy();
        httpClientPolicy.setConnectionTimeout(36000);
        httpClientPolicy.setAllowChunking(false);
        http.setClient(httpClientPolicy);

        port.doSomethingUseful();
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同样,我无法在CXF客户端API中看到允许我设置服务端点的地方.不是我能看到的.在这种情况下,目标是http://localhost/integration/webservices/mywebservices.asmx,但我可以在任何地方.当然这个行人问题以某种方式解决了?

Kev*_*vin 45

请尝试以下方法:

MyWebServicesSoap port = service.getMyWebServicesSoap12();
BindingProvider provider = (BindingProvider) port;
provider.getRequestContext().put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, endpoint); 
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或者,MyWebServices可能有其他getXXX方法采用WSDL位置的URL

  • 看看CXF团队如何做事总让我对自己不必要的过度设计代码感觉更好:) (2认同)

小智 11

在cxf 2.6.1中工作

Client client = ClientProxy.getClient(port);
client.getRequestContext().put(Message.ENDPOINT_ADDRESS, "http://some-valid-endpoint") ;
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