ham*_*med 5 java hibernate jpa cascade hibernate-mapping
我在 spring mvc 应用程序中使用 hibernate,并且有一个关于级联的问题。我看到很多类似的问题,但没有一个能回答我的问题。假设我有User
和UserPosition
对象。User
有一个集合UserPosition
,也有一个UserPosition
作为默认位置。结构是这样的:
用户:
@OneToMany(mappedBy = "user", fetch = FetchType.LAZY)
private Collection<UserPosition> userPositionCollection;
public Collection<UserPosition> getUserPositionCollection() {
return userPositionCollection;
}
public void setUserPositionCollection(Collection<UserPosition> collection) {
this.userPositionCollection = collection;
}
@OneToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(name = "default_User_Position_ID", referencedColumnName = "id")
private UserPosition defaultUserPosition;
public UserPosition getDefaultUserPosition() {
return defaultUserPosition;
}
public void setDefaultUserPosition(UserPosition defaultUserPosition) {
this.defaultUserPosition = defaultUserPosition;
}
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用户位置:
@JoinColumn(name = "user_id", referencedColumnName = "id")
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.PERSIST)
private User user;
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
@OneToOne(fetch = FetchType.LAZY, mappedBy = "defaultUserPosition", cascade = CascadeType.PERSIST)
private User defaultUserPosition;
public User getDefaultUserPosition() {
return defaultUserPosition;
}
public void setDefaultUserPosition(User defaultUserPosition) {
this.defaultUserPosition = defaultUserPosition;
}
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现在,我的问题是使用级联保存相关对象的最佳实践是什么?。事实上,我对这三种解决方案感到困惑:
解决方案一:
User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters
List<UserPosition> positionList = new ArrayList<>();
positionList.add(userPosition);
user.setDefaultUserPosition(userPosition);
user.setUserPositionCollection((Collection<UserPosition>) positionList );
session.persist(user)
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解决方案2:
User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters
userPosition.setUser(user);
userPosition.setDefaultUserPosition(user);
session.persist(userPosition)
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解决方案3(前两个解决方案的组合):
User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters
List<UserPosition> positionList = new ArrayList<>();
positionList.add(userPosition);
user.setDefaultUserPosition(userPosition);
user.setUserPositionCollection((Collection<UserPosition>) positionList );
userPosition.setUser(user);
userPosition.setDefaultUserPosition(user);
session.persist(user);
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这对我来说非常重要,所以请帮助我。cascade
哪种解决方案是正确的?财产应该在哪里?感谢您的时间。
是User
父实体,级联总是从父实体传播到子实体。
因此,用户关联变为:
@OneToMany(mappedBy = "user",
fetch = FetchType.LAZY,
cascade = CascadeType.ALL,
orphanRemoval = true)
private Collection<UserPosition> userPositionCollection;
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但对于默认位置,用户成为Child
协会的成员:
@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "default_User_Position_ID", referencedColumnName = "id")
private UserPosition defaultUserPosition;
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在UserPosition
课堂上则相反:
@JoinColumn(name = "user_id", referencedColumnName = "id")
@ManyToOne(fetch = FetchType.LAZY)
private User user;
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和
@OneToOne(fetch = FetchType.LAZY,
mappedBy = "defaultUserPosition",
cascade = CascadeType.PERSIST)
private User defaultUserPosition;
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然后,您还必须添加以下始终同步双方的实用程序方法。这些进入User
班级:
public void addUserPosition(UserPosition userPosition) {
userPositionCollection.add(userPosition);
userPosition.setUser(this);
}
public void addDefaultUserPosition(UserPosition userPosition) {
defaultUserPosition = userPosition;
userPosition.setDefaultUserPosition(this);
}
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持久逻辑变为:
User user = new User();
//some setters and getters
UserPosition userPosition = new UserPosition();
//some setters and getters
user.addUserPosition(userPosition);
user.setDefaultUserPosition(userPosition);
session.persist(user);
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