fat*_*han 14 c# mongodb mongodb-.net-driver
你能用2.0驱动程序帮助我正确运行"拉(删除)".
我有一个这样的集合,我想删除第一个跟随者字段命名为fethiye的追随者.
{
"_id": ObjectId("554e05dfc90d3d4dfcaa2aea"),
"username": "bodrum",
"followerList": [
{
"_id": ObjectId("554e0625a51586362c33c6df"),
"follower": "fethiye",
"avatar": "fethiye.png"
},
{
"_id": ObjectId("554e0625a51586362c33c6df"),
"follower": "izmir",
"avatar": "izmir.png"
}
]
}
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我该如何修复此查询?
var filter = new BsonDocument("username", "bodrum");
var update = Builders<Person>.Update.Pull("followerList:follower", "fethiye");
Person pr = collection.FindOneAndUpdateAsync(filter, update).Result;
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谢谢.
Joh*_*yHK 42
使用过滤器删除数组元素时,需要使用PullFilter构建器而不是Pull(与整个元素匹配).
var collection = db.GetCollection<Person>("people");
var filter = new BsonDocument("username", "bodrum");
var update = Builders<Person>.Update.PullFilter("followerList",
Builders<Follower>.Filter.Eq("follower", "fethiye"));
var result = collection.FindOneAndUpdateAsync(filter, update).Result;
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或者更简洁一点,使用lambdas:
var update = Builders<Person>.Update.PullFilter(p => p.followerList,
f => f.follower == "fethiye");
var result = collection
.FindOneAndUpdateAsync(p => p.username == "bodrum", update).Result;
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假设您有一个集合名称 Person,您可以使用 PullFilter 从数组中删除记录
var filterBuilder = Builders<Person>.Filter.Eq(person => person.username, "bodrum");
var updateBuilder = Builders<Person>.Update.PullFilter(p => p.followerList,
Builders<Person>.Filter.Eq(per => per.follower, "fethiye"));
var updateResult = collection.UpdateOne(filterBuilder, updateBuilder);
Console.WriteLine(
$"MatchedCount: {updateResult.MatchedCount}, ModifiedCount: {updateResult.ModifiedCount}");
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如果我们还需要删除过滤文档中的值数组,我们可以用这一行替换更新构建器
var updateBuilder = Builders<Person>.Update.PullFilter(p => p.followerList,
Builders<Person>.Filter.In(per => per.follower, new List<string> {"fethiye", "izmir"}));
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也可以保存很多文档,updateOne 可以替换为 updateMany
var updateResult = collection.UpdateMany(filterBuilder, updateBuilder);
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