这是一个解决方案。首先定义函数组号:
(defun group-number (num &optional size char)
"Format NUM as string grouped to SIZE with CHAR."
;; Based on code for `math-group-float' in calc-ext.el
(let* ((size (or size 3))
(char (or char ","))
(str (if (stringp num)
num
(number-to-string num)))
;; omitting any trailing non-digit chars
;; NOTE: Calc supports BASE up to 36 (26 letters and 10 digits ;)
(pt (or (string-match "[^0-9a-zA-Z]" str) (length str))))
(while (> pt size)
(setq str (concat (substring str 0 (- pt size))
char
(substring str (- pt size)))
pt (- pt size)))
str))
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Next, use it in your formula:
| | | |
|-----------+-------+-------------|
| 2000 | 3100 | 5,100 |
| 11 | 22 | 33 |
| 111221212 | 29996 | 111,251,208 |
| | | 0 |
#+TBLFM: $3='(group-number (+ $1 $2));N
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这里我们使用group-number函数来格式化 emacs lisp 表单的结果 - 而不是使用计算公式语法。