我正在开发一个小函数来获取一个url并根据它所在的位置返回一个相对路径.
如果url在查询字符串中包含路径,则pathinfo返回不正确的结果.以下代码证明了这一点:
$p = 'http://localhost/demos/image_editor/dir_adjuster.php?u=http://localhost/demos/some/dir/afile.txt';
$my_path_info = pathinfo($p);
echo $p . '<br/><pre>';
print_r($my_path_info);
echo '</pre>';
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该代码输出:
http://localhost/demos/image_editor/dir_adjuster.php?u=http://localhost/demos/some/dir/afile.txt
Array
(
[dirname] => http://localhost/demos/image_editor/dir_adjuster.php?u=http://localhost/demos/some/dir
[basename] => afile.txt
[extension] => txt
[filename] => afile
)
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这显然是错的.任何解决方法?
任何解决方法?
是的,做得对 ;)
$url = urlencode('http://localhost/demos/some/dir/afile.txt');
$p = 'http://localhost/demos/image_editor/dir_adjuster.php?u='.$url;
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对于URL,尤其是具有查询字符串的URL,parse_url()提取路径组件应该更可靠; 之后,运行pathinfo()它.