如何确保两个将在构造函数大小中传递的向量等于？

Question

我实现了一个类:

public class TableInfoGroup {
  Vector<TableInfo> tableInfoVector;
  public TableInfoGroup(Vector<String> tableNameVector, Vector<String> tableTagIdVector)
  {
    if (tableNameVector.size() != tableTagIdVector.size())
      return;//I think it's not proper to do this
    tableInfoVector = new Vector<TableInfo>();
    for(int i = 0; i < tableNameVector.size(); i++)
      tableInfoVector.add(new TableInfo(tableNameVector.get(i), tableTagIdVector.get(i)));
  }
}

怎么做那优雅？抛出异常？谢谢.

Answer 1

就个人而言,我会让方法抛出IllegalArgumentException:

抛出以指示方法已被传递非法或不适当的参数.

例如:

if (tableNameVector.size() != tableTagIdVector.size())
  throw new IllegalArgumentException("tableNameVector and tableTagIdVector " +
                                     "must have the same size");

即使IllegalAgumentException是未经检查的异常,我仍然会将其作为文档添加到方法的throws子句中.

使构造函数抛出异常会阻止构造对象,我认为这是正确的操作过程.