如何将文件上传到Amazon S3并使用iOS获取响应的URL

Question

我使用了Amazon Sample Code中的代码片段.以下代码将数据上传到amazon S3存储桶,但我需要上传文件的URL.我正朝着正确的方向前进吗？或者有人能指出我正在犯的错误

任何形式的帮助将不胜感激.

AWSS3TransferManager *transferManager = [AWSS3TransferManager defaultS3TransferManager];
    AWSS3TransferManagerUploadRequest *uploadRequest = [AWSS3TransferManagerUploadRequest new];
    uploadRequest.bucket = S3BucketName;
    uploadRequest.key = S3UploadKeyName;
    uploadRequest.body = self.uploadFileURL;
    //uploadRequest.contentLength = [NSNumber numberWithUnsignedLongLong:fileSize];

    [[transferManager upload:uploadRequest] continueWithBlock:^id(BFTask *task) {
        // Do something with the response
        AWSS3TransferManagerUploadOutput *uploadOutPut = task.result;
        NSLog(@"bftask:%@",uploadOutPut); // Upload out put gives me the following response
        return nil;
    }];

---

bfTask响应:

bftask:<AWSS3TransferManagerUploadOutput: 0x1706606c0> {
    ETag = "\"0aefedfa36b687a74025b1ad50f3101f\"";
    serverSideEncryption = 0;
}

Answer 1

如果您只需要下载该文件,则可以使用AWSS3TransferManagerDownloadRequestSDK下载文件.或者,您可以使用AWSS3PreSignedURLBuilder生成预签名URL来下载文件.

如果您只想知道对象的URL,则URL遵循以下模式:

https://<YourS3Endpoint>/<YourBucketName>/<YourObjectKeyName>

Amazon S3中的任何对象默认都是私有的,不可公开读取.如果你想让它公开可读,你需要设置ACL你的AWSS3TransferManagerUploadRequest对象.

有关更多详细信息,请参阅Amazon S3 Bucket公共访问注意事项.