Cha*_*kar 8 php mysql jquery typeahead.js
我使用twitter typeahead和php作为后端从mysql获取数据.但是当我开始在文本框中输入时,我无法看到任何建议.我认为因为php输出必须是JSON编码..
我该如何编码输出
输出:
echo '<a href="results.html" class="searchres" onclick="navigate()" style="color:#696969;text-decoration:none;"><img src='.$iurl.' class="icons" /><div class="results" style="color:#696969;text-decoration:none;">'."$fname".'</div><span style="color:#696969;text-decoration:none;" class="author">'.$caption.'</span></a>'."\n";
HTML:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Example of Twitter Typeahead</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript" src="../js/typeahead.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('input.typeahead').typeahead({
name: 'countries',
prefetch: 'getvalues.php',
limit: 10
});
});
</script>
<style type="text/css">
.bs-example{
font-family: sans-serif;
position: relative;
margin: 100px;
}
.typeahead, .tt-query, .tt-hint {
border: 2px solid #CCCCCC;
border-radius: 8px;
font-size: 24px;
height: 30px;
line-height: 30px;
outline: medium none;
padding: 8px 12px;
width: 396px;
}
.typeahead {
background-color: #FFFFFF;
}
.typeahead:focus {
border: 2px solid #0097CF;
}
.tt-query {
box-shadow: 0 1px 1px rgba(0, 0, 0, 0.075) inset;
}
.tt-hint {
color: #999999;
}
.tt-dropdown-menu {
background-color: #FFFFFF;
border: 1px solid rgba(0, 0, 0, 0.2);
border-radius: 8px;
box-shadow: 0 5px 10px rgba(0, 0, 0, 0.2);
margin-top: 12px;
padding: 8px 0;
width: 422px;
}
.tt-suggestion {
font-size: 24px;
line-height: 24px;
padding: 3px 20px;
}
.tt-suggestion.tt-is-under-cursor {
background-color: #0097CF;
color: #FFFFFF;
}
.tt-suggestion p {
margin: 0;
}
</style>
</head>
<body>
<div class="bs-example">
<input type="text" class="typeahead tt-query" autocomplete="off" spellcheck="false">
</div>
</body>
</html>
getvalues.php
<?php
require_once "config.php";
$q = strtolower($_GET["q"]);
if (!$q) return;
$sql = "select file_name,img_url,captions from completer";
$rsd = mysql_query($sql);
while($rs = mysql_fetch_array($rsd)) {
$fname = $rs['file_name'];
$iurl = $rs ['img_url'];
$caption = $rs ['captions'];
echo '<a href="results.html" class="searchres" onclick="navigate()" style="color:#696969;text-decoration:none;"><img src='.$iurl.' class="icons" /><div class="results" style="color:#696969;text-decoration:none;">'."$fname".'</div><span style="color:#696969;text-decoration:none;" class="author">'.$caption.'</span></a>'."\n";
}
?>
小智 0
您可能希望将预输入列表放入 json 文件中，并将脚本更改为：
$(document).ready(function(){
$('input.typeahead').typeahead({
name: 'countries',
prefetch: 'location/getvalues.json',
limit: 10
});
});
json 文件应该是：
["country1","country2","country3"]
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