获取MySQL下个月的第一个和最后一个日期

Question

如何将下个月的第一天和最后一天用于where子句？

Answer 1

使用:

SELECT

DATE_SUB(
    LAST_DAY(
        DATE_ADD(NOW(), INTERVAL 1 MONTH)
    ), 
    INTERVAL DAY(
        LAST_DAY(
            DATE_ADD(NOW(), INTERVAL 1 MONTH)
        )
    )-1 DAY
) AS firstOfNextMonth,

LAST_DAY(
    DATE_ADD(NOW(), INTERVAL 1 MONTH)
)AS lastOfNextMonth

Answer 2

对于下个月的最后一天,您可以使用以下LAST_DAY()功能:

SELECT LAST_DAY(DATE_ADD(CURDATE(), INTERVAL 1 MONTH));
+-------------------------------------------------+
| LAST_DAY(DATE_ADD(CURDATE(), INTERVAL 1 MONTH)) |
+-------------------------------------------------+
| 2010-07-31                                      |
+-------------------------------------------------+
1 row in set (0.00 sec)

一些测试边缘情况:

SELECT LAST_DAY(DATE_ADD('2010-01-31', INTERVAL 1 MONTH));
+----------------------------------------------------+
| LAST_DAY(DATE_ADD('2010-01-31', INTERVAL 1 MONTH)) |
+----------------------------------------------------+
| 2010-02-28                                         |
+----------------------------------------------------+
1 row in set (0.00 sec)

SELECT LAST_DAY(DATE_ADD('2010-02-28', INTERVAL 1 MONTH));
+----------------------------------------------------+
| LAST_DAY(DATE_ADD('2010-02-28', INTERVAL 1 MONTH)) |
+----------------------------------------------------+
| 2010-03-31                                         |
+----------------------------------------------------+
1 row in set (0.00 sec)

SELECT LAST_DAY(DATE_ADD('2010-08-31', INTERVAL 1 MONTH));
+----------------------------------------------------+
| LAST_DAY(DATE_ADD('2010-08-31', INTERVAL 1 MONTH)) |
+----------------------------------------------------+
| 2010-09-30                                         |
+----------------------------------------------------+
1 row in set (0.00 sec)

这个函数也很难用到DATE_FORMAT()一个月的第一天.您可以按如下方式使用它:

SELECT DATE_FORMAT(DATE_ADD(CURDATE(), INTERVAL 1 MONTH), '%Y-%m-01');
+---------------------------------------------------------------+
| DATE_FORMAT(DATE_ADD(CURDATE(), INTERVAL 1 MONTH),'%Y-%m-01') |
+---------------------------------------------------------------+
| 2010-07-01                                                    |
+---------------------------------------------------------------+
1 row in set (0.00 sec)

因此:

SELECT   DATE_FORMAT(DATE_ADD(CURDATE(), INTERVAL 1 MONTH), '%Y-%m-01') AS
            FirstDayOfNextMonth,
         LAST_DAY(DATE_ADD(CURDATE(), INTERVAL 1 MONTH)) AS
            LastDayOfNextMonth;

+---------------------+--------------------+
| FirstDayOfNextMonth | LastDayOfNextMonth |
+---------------------+--------------------+
| 2010-07-01          | 2010-07-31         |
+---------------------+--------------------+
1 row in set (0.00 sec)

Answer 3

下个月的第一天就是本月的最后一天+ 1:

select adddate(last_day(curdate()), 1)

最后一天下个月简直是(今天+ 1个月)的最后一天:

select last_day(curdate() + interval 1 month))

这些是最直接的解决方案.你将无法找到一个较短的.

如果你需要的第一天,当前月,看到/sf/answers/2027680651/