Python:TypeError:__ init __()只需2个参数(给定1个)

Question

我知道这个问题已被问过几次,但没有一个能够为我提供解决方案.我看了这些:

__init __()只需要2个参数(给定1个)？

class __init __()只需2个参数(给定1个)

我所要做的就是为"生存游戏"创建两个类,就像一个非常糟糕的我的世界版本.Bellow是这两个类的完整代码:

class Player:
    '''
    Actions directly relating to the player/character.
    '''
    def __init__(self, name):
        self.name = name
        self.health = 10
        self.shelter = False

    def eat(self, food):
        self.food = Food
        if (food == 'apple'):
            Food().apple()

        elif (food == 'pork'):
            Food().pork()

        elif (food == 'beef'):
            Food().beef()

        elif (food == 'stew'):
            Food().stew()

class Food:
    '''
    Available foods and their properties.
    '''
    player = Player()

    def __init__(self):
        useless = 1
        Amount.apple = 0
        Amount.pork = 0
        Amount.beef = 0
        Amount.stew = 0

    class Amount:   
        def apple(self):
            player.health += 10

        def pork(self):
            player.health += 20

        def beef(self):
            player.health += 30

        def stew(self):
            player.health += 25      

现在为了完整的错误:

Traceback (most recent call last):
  File    "/home/promitheas/Desktop/programming/python/pygame/Survive/survive_classe  s.py", line 26, in <module>
    class Food:
  File     "/home/promitheas/Desktop/programming/python/pygame/Survive/survive_classe    s.py", line 30, in Food
    player = Player()
TypeError: __init__() takes exactly 2 arguments (1 given)

我只是想让课程有效.

Answer 1

您使用的代码如下:

player = Player()

这是一个问题,因为__init__必须由name根据您的代码调用的一个参数提供.因此,要解决您的问题,只需为Player构造函数提供一个名称,您就可以了:

player = Player('sdfasf')