python for循环遍历值不在指定的范围内

Question

我有一个包含列表的python代码dict,其中每个元素都是任意大小的列表.我循环遍历元素如下:

for i in range(len(dict)):
    for j in range(1,len(dict[i])):
        str = dict[i][j]

在这一点上,我得到一个错误说IndexError: list index out of range.我正在使用,range(1,len(dict))因为我想跳过每个列表的第一个元素dict.在产生错误的位置,i=5,len(dict[5])=2,所以j要遍历只1,但是当我检查的j价值,我得到2.这怎么可能？

甚至更奇怪的是当我在python控制台中输入上面的代码时,我没有得到这样的错误,一切正常.

编辑:完整代码是:(注意从更改dict到keywords)

import re

conds = [['emerald cryo i&ii,a,01', '40% (v/v) mpd', 'sodium phosphate dibasic', 'citric acid'],['emerald cryo i&ii,a,02', '40% (v/v) ethylene glycol', 'sodium acetate', 'acetic acid'],['emerald cryo i&ii,a,03', '50% (v/v) peg-200', 'citrate', 'na']]

keywords = [["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na acetate'", " 'na_acetate'"],["'rbcl+mgcl2'", " 'rbcl+mgcl2 (0.025m each)'"]]

#cycle through elements to see if there is a match to the dictionary
for i in range(len(keywords)):
    for j in range(1,len(keywords[i])):
        print j
        for k in range(len(conds)):
            str = keywords[i][j].strip().strip("'").strip() #this is where the error occurs
            match = [(str == l) for l in conds[k]]
            ind = [i for i, x in enumerate(match) if x]
            if len(ind) !=0:
                print ind
                print str

实际conds和keywords列表更长,并从文件中读入,但我只是从python控制台复制并粘贴了两个元素.

编辑2:打印出来i,j,len(dict[i]),dict[i]在内部循环.输出太长了,不能放在这里,但这是一个浓缩版本:

0 1 3 ["'potassium acetate'", " 'k(oac)'", " 'potassium acetate'"]
3 1 3 ["'ammonium nitrate'", " '(nh4)2(no)3'", " 'ammonium nitrate'"]
3 1 3 ["'ammonium nitrate'", " '(nh4)2(no)3'", " 'ammonium nitrate'"]
3 1 3 ["'ammonium nitrate'", " '(nh4)2(no)3'", " 'ammonium nitrate'"]
4 1 5 ["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na acetate'", " 'na_acetate'"]
4 1 5 ["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na acetate'", " 'na_acetate'"]
5 1 2 ["'rbcl+mgcl2'", " 'rbcl+mgcl2 (0.025m each)'"]
4 1 5 ["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na acetate'", " 'na_acetate'"]
4 1 5 ["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na acetate'", " 'na_acetate'"]
3 1 3 ["'ammonium nitrate'", " '(nh4)2(no)3'", " 'ammonium nitrate'"]
3 1 3 ["'ammonium nitrate'", " '(nh4)2(no)3'", " 'ammonium nitrate'"]
4 1 5 ["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na acetate'", " 'na_acetate'"]
[2]
sodium acetate
4 1 5 ["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na acetate'", " 'na_acetate'"]
4 1 5 ["'sodium acetate'", " 'sodium acetate'", " 'na(ac)'", " 'na     acetate'", " 'na_acetate'"]
5 1 2 ["'rbcl+mgcl2'", " 'rbcl+mgcl2 (0.025m each)'"]

...

5 2 2 ["'rbcl+mgcl2'", " 'rbcl+mgcl2 (0.025m each)'"]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "coarseCondEdit.py", line 38, in <module>
    str = keywords[i][j].strip().strip("'").strip()
IndexError: list index out of range

Answer 1

这条线

ind = [i for i, x in enumerate(match) if x]

改变你i用于外循环的那个.

如果您使用普通的Python循环而不是索引循环,那就不会发生这种情况:

for words in keywords:
    for word in words[1:]:
        for cond in conds:
            word = word.strip().strip("'").strip()
            match = [(word == l) for l in cond]
            ind = [i for i, x in enumerate(match) if x]
            if len(ind) !=0:
                print ind
                print word

这不是看起来更好,更有意义吗？

变量名称可以进一步改进,但我会把它留给你,因为我不知道你的东西的名称.