如何在代码上添加用户输入

Jer*_*cis 2 java loops user-input binary-search

我想从用户获取用户输入并进行非递归二进制搜索可以任何人告诉我如何做它会不胜感激

public class Main {
// binarySeach: non-recursive
   public int Main(int[] a, int x) {
      int low = 0;
  int high = a.length - 1;
  while (low <= high) {
     int mid = (low + high)/2;
     if (a[mid] == x) return mid;
     else if (a[mid] < x) low = mid + 1;
     else high = mid - 1;
  }
  return -1;
  }



 public static void main(String[] args) {
      Main bin = new Main();
  int[] a =
    { 2, 8,12,14,16,19,24,28,31,33,// 0-9
     39,40,45,49,51,53,54,56,57,60,// 10-19
     63,69,77,82,88,89,94,96,97};  // 20-28
  for (int i = 0; i < a.length; i++)
     System.out.print(bin.Main(a,
        a[i]) + " ");   

  System.out.println();
}
}
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KM1*_*M11 5

public static void main(String[] args) {
    Main bin = new Main();
    int[] a = { 2, 8,12,14,16,19,24,28,31,33,// 0-9
                39,40,45,49,51,53,54,56,57,60,// 10-19
                63,69,77,82,88,89,94,96,97};  // 20-28
    Scanner userinput = new Scanner(System.in);
    System.out.println("Enter number to search");
    int n = userinput.nextInt();
    System.out.println("Number index: "+bin.Main(a, n));
}
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注意第一个位置/索引是0,所以如果你想获得数字12而不是索引2的数字索引3,System.out.println("Number index: "+bin.Main(a, n));改为System.out.println("Number index: "(bin.Main(a, n)+1));