gal*_*lex 4 sql group-by aggregation apache-spark
我有一个RDD包含一个名为time long类型的时间戳:
root
|-- id: string (nullable = true)
|-- value1: string (nullable = true)
|-- value2: string (nullable = true)
|-- time: long (nullable = true)
|-- type: string (nullable = true)
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我试图将value1,value2和time分组为YYYY-MM-DD.我试图按强制分组(时间为日期),但后来我收到以下错误:
Exception in thread "main" java.lang.reflect.InvocationTargetException
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at org.apache.spark.deploy.worker.DriverWrapper$.main(DriverWrapper.scala:40)
at org.apache.spark.deploy.worker.DriverWrapper.main(DriverWrapper.scala)
Caused by: java.lang.RuntimeException: [1.21] failure: ``DECIMAL'' expected but identifier Date found
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这是否意味着没有办法按日期分组?我甚至试图添加另一个级别的转换以将其作为String:
cast(cast(time as Date) as String)
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哪个返回相同的错误.
我已经读过,我可能在RDD上使用了可能的aggregateByKey,但我不明白如何将它用于几列并将其转换为YYYY-MM-DD字符串.我该怎么办?
我通过添加这些功能解决了这个问题:
def convert( time:Long ) : String = {
val sdf = new java.text.SimpleDateFormat("yyyy-MM-dd")
return sdf.format(new java.util.Date(time))
}
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并将其注册到sqlContext中,如下所示:
sqlContext.registerFunction("convert", convert _)
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然后我可以按日期分组:
select * from table convert(time)
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