MySql | 分面搜索已更改

Question

也许你会帮助我查询我的SQL.我的问题是基于另一个问题:Mysql | 分面搜索 一切都是一样的,我需要相同的结果,但表格略有不同.我无法构建我的查询.请看看这个sql小提琴:

我的表结构:

CREATE TABLE products
    (`id` int, `description` varchar(9), `user_id` int);

INSERT INTO products
    (`id`, `description`, `user_id`)
VALUES
    (1, 'my car', 3),
    (2, 'dream car', 3),
    (3, 'New car', 3),
    (4, 'Old car', 4);

CREATE TABLE fields
    (`id` int, `field_name` varchar(14)); /*meta_name*/

INSERT INTO fields
    (`id`, `field_name`)
VALUES
    (1, 'Make'),
    (2, 'Model'),
    (3, 'Color'),
    (4, 'Car Type'),
    (5, 'Interior Color');

CREATE TABLE fields_values
    (`id` int, `field_id` int, `field_value` varchar(7)); /*meta_value*/

INSERT INTO fields_values
    (`id`, `field_id`, `field_value`)
VALUES
    (1, 1, 'BMW'),
    (2, 2, '3Series'),
    (3, 3, 'White'),
    (4, 4, 'Coupe'),
    (5, 5, 'Black'),
    (6, 1, 'BMW'),
    (7, 2, '2Series'),
    (8, 3, 'Black'),
    (9, 4, 'Coupe'),
    (10, 5, 'Grey'),
    (11, 1, 'Honda'),
    (12, 2, 'Civic'),
    (13, 3, 'Red'),
    (14, 4, 'Sedan'),
    (15, 5, 'Black');

CREATE TABLE products2fields_values
    (`id` int, `product_id` int, `field_value_id` int);
INSERT INTO products2fields_values
    (`id`, `product_id`, `field_value_id`)
VALUES
    (1, 1, 1),
    (2, 1, 2),
    (3, 1, 3),
    (4, 1, 4),
    (5, 1, 5),
    (6, 2, 1),
    (7, 2, 2),
    (8, 2, 3),
    (9, 2, 4),
    (10, 2, 5),
    (11, 3, 1),
    (12, 3, 2),
    (13, 3, 3),
    (14, 3, 4),
    (15, 3, 5); 

我的错误查询:

SELECT field_name, field_value, COUNT(DISTINCT pid) count
FROM fields ft 
JOIN fields_values fvt
    ON fvt.field_id = ft.id

JOIN products2fields_values p2fv
    ON p2fv.field_value_id = fvt.id

LEFT JOIN (
    SELECT p.id pid
    FROM products p   
    JOIN products2fields_values p2fv
        ON p2fv.product_id = p.id
    JOIN fields_values fvt
        ON fvt.id = p2fv.field_value_id
    JOIN fields ft
        ON ft.id = fvt.field_id
    GROUP BY p.id
    HAVING MAX(ft.id = 1 AND p2fv.field_value_id = 1) = 1
       AND MAX(ft.id = 4 AND p2fv.field_value_id = 4) = 1
)

LJ ON p2fv.product_id = LJ.pid
GROUP BY field_name, field_value;

我想要得到结果:

|      field_name| field_value| count |
|----------------|------------|-------|
|       Car Type |      Coupe |     2 |
|       Car Type |      Sedan |     0 |
|          Color |      Black |     1 |
|          Color |        Red |     0 |
|          Color |      White |     1 |
| Interior Color |      Black |     2 |
| Interior Color |       Grey |     1 |
|           Make |        BMW |     2 |
|           Make |      Honda |     0 |
|          Model |    2Series |     0 |
|          Model |    3Series |     1 |
|          Model |      Civic |     0 |

Answer 1

据我了解您的问题，这应该是您想要的查询：

SELECT field_name, field_value, COUNT(val.id) as count
FROM fields ft 
JOIN fields_values fvt
ON fvt.field_id = ft.id
LEFT JOIN products2fields_values val
ON val.field_value_id = fvt.id 
GROUP BY  field_name, field_value;

我不知道您为什么要加入产品表，因为它对于您的结果似乎没有必要。我不明白你为什么实施你奇怪的HAVING条款。

请看一下我的查询结果。