用 diffgram 解析复杂的肥皂响应

Question

我无法解析来自 .net 网络服务的以下soap 响应，我得到两种类型的响应，一种是我解析过的任何类型格式，但现在我需要解析以下 xml

<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
   <soap:Body>
      <GetReminderResponse xmlns="http://tempuri.org/">
         <GetReminderResult>
            <xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
               <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
                  <xs:complexType>
                     <xs:choice minOccurs="0" maxOccurs="unbounded">
                        <xs:element name="Table">
                           <xs:complexType>
                              <xs:sequence>
                                 <xs:element name="RemMessage" type="xs:string" minOccurs="0"/>
                                 <xs:element name="InvM_Id" type="xs:int" minOccurs="0"/>
                                 <xs:element name="DocType" type="xs:int" minOccurs="0"/>
                                 <xs:element name="PrmR_TypeId" type="xs:int" minOccurs="0"/>
                                 <xs:element name="PrmR_Id" type="xs:int" minOccurs="0"/>
                              </xs:sequence>
                           </xs:complexType>
                        </xs:element>
                     </xs:choice>
                  </xs:complexType>
               </xs:element>
            </xs:schema>
            <diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
               <NewDataSet xmlns="">
                  <Table diffgr:id="Table1" msdata:rowOrder="0">
                     <RemMessage>Exeed Discount Limit on Invoice dated on 04/05/2015 for  ANDREA NORONHA , from 3 - Lokhandwala Showroom</RemMessage>
                     <InvM_Id>78455</InvM_Id>
                     <DocType>3</DocType>
                     <PrmR_TypeId>3</PrmR_TypeId>
                     <PrmR_Id>2213</PrmR_Id>
                  </Table>
                  <Table diffgr:id="Table2" msdata:rowOrder="1">
                     <RemMessage>Exeed Discount Limit on Invoice dated on 04/05/2015 for ADITI SHAH , from 3 - Lokhandwala Showroom</RemMessage>
                     <InvM_Id>78456</InvM_Id>
                     <DocType>3</DocType>
                     <PrmR_TypeId>3</PrmR_TypeId>
                     <PrmR_Id>2214</PrmR_Id>
                  </Table>
               </NewDataSet>
            </diffgr:diffgram>
         </GetReminderResult>
      </GetReminderResponse>
   </soap:Body>
</soap:Envelope>

Answer 1

你的肥皂响应中有数据类型的模式，这对我来说完全奇怪。但是我已经构建了忽略 xs:schema 部分并创建 GetReminder 对象数组的代码（类型取自您之前的帖子：How to parse diffgram anytype response from .net webservice）。我认为，更好的主意是为结构创建 KVMSerializables，但它下面的方式也很好用 ;)

   ArrayList<GetReminder> lst = new ArrayList<GetReminder>();
   if(envelope.bodyIn instanceof SoapObject && envelope.bodyIn!=null){
       SoapObject so=(SoapObject)envelope.bodyIn;
        if(so.hasProperty("GetReminderResult")){
            SoapObject so1 = (SoapObject) so.getProperty("GetReminderResult");
            if(so1.hasProperty("diffgram")){
                SoapObject soDiffg = (SoapObject) so1.getProperty("diffgram");
                if(soDiffg.hasProperty("NewDataSet")){
                    SoapObject soNDSet = (SoapObject) soDiffg.getProperty("NewDataSet");

                    for (int i = 0; i < soNDSet.getPropertyCount(); i++) {
                        SoapObject soRem = (SoapObject) soNDSet.getProperty(i);
                        GetReminder reminder = new GetReminder();

                        if (soRem.hasProperty("RemMessage")) {
                            reminder.setRemMessage(soRem.getPropertyAsString("RemMessage"));
                        }
                        if (soRem.hasProperty("InvM_Id")) {
                            reminder.setInvM_Id(Integer.valueOf(soRem.getPropertyAsString("InvM_Id")));
                        }
                        if (soRem.hasProperty("DocType")) {
                            reminder.setDocType(Integer.valueOf(soRem.getPropertyAsString("DocType")));
                        }
                        if (soRem.hasProperty("PrmR_TypeId")) {
                            reminder.setPrmR_TypeId(Integer.valueOf(soRem.getPropertyAsString("PrmR_TypeId")));
                        }
                        if (soRem.hasProperty("PrmR_Id")) {
                            reminder.setPrmR_Id(Integer.valueOf(soRem.getPropertyAsString("PrmR_Id")));
                        }

                        lst.add(reminder);
                    }
                }
            }
       }
    }

   System.out.println(lst.size());

问候， 马辛