Jus*_*ser 5 php laravel laravel-4 laravel-5
我尝试进行以下复杂的连接,以获得根据学生分部开始的所有科目
$studentID = Student::find($id);
$divisionID = Student::where('id', $studentID->id)->select('division_id')->pluck('division_id');
$payments = Payment::all();
$discounts = Discount::all();
// This the Big join to get all subjects that started according to the student's division
$subjectStart = SubjectStart::join('teacher_subject' ,'teacher_subject.id' ,'=','subject_start.teach_sub_id')
->join('subject' ,'subject.id' ,'=' , 'teacher_subject.subject_id')
->join('subject_division','subject_division.subject_id' ,'=' ,'subject.id')
->join('division' ,'division.id','=','subject_division.division_id')
->where('division.id' ,$divisionID)
->where('lecture_num' ,'>' , 0)
->get();
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之后,我试图循环$ subjectStart如下
@foreach($subjectStart as $st)
{{$st->id}}
{{$st->start_date}}
{{$st->lecture_num}}
.............
@endforeach
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除了$ st-> id之外,join的结果显示正确,显示为division_id而不是subject_start_id,例如,如果除法_id = 5,则循环超过$ subjectStart,$ st-> id将为5,5,5,. ....
有什么建议 ?
我解决了它只是使用 select 语句如下
// This the Big join to get all subjects that started according to the student's division
$subjectStart = SubjectStart::join('teacher_subject' ,'teacher_subject.id' ,'=','subject_start.teach_sub_id')
->join('subject' ,'subject.id' ,'=' , 'teacher_subject.subject_id')
->join('subject_division','subject_division.subject_id' ,'=' ,'subject.id')
->join('division' ,'division.id','=','subject_division.division_id')
->where('division.id' ,$divisionID)
->where('lecture_num' ,'>' , 0)
->select('subject_start.id', 'subject_start.teach_sub_id', 'subject_start.group_id','subject_start.lecture_num','subject_start.start_date')
->get();
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