'mov'的内存引用太多

Question

我已经查看了有关如何解决这个问题的所有建议线程,我找不到符合我的错误的线程.

当我编译时,我得到"'mov'的"太多内存参考",即使我拿出所有这些...？

__asm__(
    "mov    0x8(%ebp),  %edx;"
    "mov    0x8(%edx),  %edx;"
    "cmp        $0x0,       %edx;"
    "je     notFound;"

    "sub        $0x10,      %esp;"
    "movl   0xc(%ebp),  (%esp);"
    "movl   $0x24,      0x8(%esp);"


    "mainloop: "
    "movl   %edx,       0x4(%esp);"
    "call _memcmp;"
    "cmp        $0xffffffff,    %eax;"
    "je     leftBranch;"

    "cmp        $0x1,       %eax;"
    "je     rightBranch;"
    "jne        found;"


    "leftBranch: "
    "mov    0xc(%edx),  %edx;"
    "cmp        $0x0,       %edx;"
    "je     notFound;"
    "jne        mainloop;"

    "rightBranch: "
    "mov    0x10(%edx), %edx;"
    "cmp        $0x0,       %edx;"
    "je     notFound;"
    "jne        mainloop;"

    "notFound: "
    "mov    $0x0,       %eax;"
    "add        $0x10,      %esp;"  
    "leave;"
    "ret;"

    "found: "
    "add        $0x10,      %esp;"
    "leave;"
    "ret;"
);

Answer 1

问题很可能是这一行:

"movl   0xc(%ebp),  (%esp);"

您不能在单个指令中引用两个内存位置mov.