Swift按对象值的属性对字典进行排序

Question

我有一本字典<String,Loto>,Loto就像下面的对象;

Loto:   
 {
    "success": true,
    "data": {
    "oid": "64kbbqi8dbxygb00",
    "hafta": 961,
    "buyukIkramiyeKazananIl": "",
    "cekilisTarihi": "11/04/2015",
    "cekilisTuru": "SAYISAL_LOTO",
    "rakamlar": "03#02#48#16#15#08",
    "rakamlarNumaraSirasi": "02 - 03 - 08 - 15 - 16 - 48",
    "devretti": false,
    "devirSayisi": 0,
    "bilenKisiler": [
    {
    "oid": "64kbbxi8dbxyg403",
    "kisiBasinaDusenIkramiye": 7.35,
    "kisiSayisi": 185712,
    "tur": "$3_BILEN"
    },
    {
    "oid": "64kbbxi8dbxyg402",
    "kisiBasinaDusenIkramiye": 53.05,
    "kisiSayisi": 9146,
    "tur": "$4_BILEN"
    },
    {
    "oid": "64kbbxi8dbxyg401",
    "kisiBasinaDusenIkramiye": 4532.2,
    "kisiSayisi": 142,
    "tur": "$5_BILEN"
    },
    {
    "oid": "64kbbxi8dbxyg400",
    "kisiBasinaDusenIkramiye": 1528438.75,
    "kisiSayisi": 1,
    "tur": "$6_BILEN"
    }
    ],
    "buyukIkrKazananIlIlceler": [
    {
    "il": "10",
    "ilView": "BALIKESÄ°R",
    "ilce": "01001",
    "ilceView": "AYVALIK"
    }
    ],
    "kibrisHasilati": 51127,
    "devirTutari": 0.09,
    "kolonSayisi": 10537872,
    "kdv": 1599672.97,
    "toplamHasilat": 10537872,
    "hasilat": 8938199.03,
    "sov": 893819.9,
    "ikramiyeEH": 8044379.129999999,
    "buyukIkramiye": 1528432.03,
    "haftayaDevredenTutar": 0
    }
    }

所以我的字典像<"11042015",Loto>,我想通过loto对象的"hafta"属性对这本词典进行排序.

我怎样才能做到这一点？请帮我!

Answer 1

如果Loto是具有hafta属性的对象,则可以通过将字典传递给sorted函数来对字典进行排序,以及一个告诉它如何对条目进行排序的闭包:

sorted(dict) { $0.1.hafta < $1.1.hafta }

($0.1并且$1.1因为字典作为键/值对的序列出现 - 您希望按值的属性排序,即元组条目1)

注意,这将返回一个排序数组,类型[(String,Loto)]对,而不是字典(因为Swift字典是无序的).

(如果Loto不是真正的对象,而是另一个字典,你可能需要这样做{$0.1["hafta"] < $1.1["hafta"]}- 这实际上取决于你如何保存你的数据 - 好消息是你不需要担心选项,因为它们可以与之比较<)

如果您不需要密钥,只需对值进行排序:

sorted(dict.values) { $0.hafta < $1.hafta }

这将返回一个排序的类型数组 [Loto]