products
+----+--------+
| id | title |
+----+--------+
| 1 | Apple |
| 2 | Pear |
| 3 | Banana |
| 4 | Tomato |
+----+--------+
product_variants
+----+------------+------------+
| id | product_id | is_default |
+----+------------+------------+
| 1 | 1 | 0 |
| 2 | 1 | 1 |
| 3 | 2 | 1 |
| 4 | 3 | 1 |
| 5 | 4 | 1 |
+----+------------+------------+
properties
+----+-----------------+-----------+
| id | property_key_id | value |
+----+-----------------+-----------+
| 1 | 1 | Yellow |
| 2 | 1 | Green |
| 3 | 1 | Red |
| 4 | 2 | Fruit |
| 5 | 2 | Vegetable |
| 6 | 1 | Blue |
+----+-----------------+-----------+
property_keys
+----+-------+
| id | value |
+----+-------+
| 1 | Color |
| 2 | Type |
+----+-------+
product_has_properties
+----+------------+-------------+
| id | product_id | property_id |
+----+------------+-------------+
| 1 | 1 | 4 |
| 2 | 1 | 3 |
| 3 | 2 | 4 |
| 4 | 3 | 4 |
| 5 | 3 | 4 |
| 6 | 4 | 4 |
| 7 | 4 | 5 |
+----+------------+-------------+
product_variant_has_properties
+----+------------+-------------+
| id | variant_id | property_id |
+----+------------+-------------+
| 1 | 1 | 2 |
| 2 | 1 | 3 |
| 3 | 2 | 6 |
| 4 | 3 | 4 |
| 5 | 4 | 1 |
| 6 | 5 | 1 |
+----+------------+-------------+
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我需要查询我的数据库,以便选择products哪些properties附加到产品本身或者将这些属性附加到其中一个相关的数据库product_variants.也应该properties使用相同的properties.property_key_id进行分组,如下所示:(pkey1='red' OR pkey1='blue') AND (pkey2='fruit' OR pkey2='vegetable')
示例案例:
(color='red' AND type='vegetable').这应该只返回番茄.((color='red' OR color='yellow') AND type='fruit')应该返回Apple和Banana请注意,在上面的示例中,我不需要通过properties.value进行查询,我可以通过properties.id进行查询.
我使用MySQL查询玩了很多,但我遇到的最大问题是通过两个数据透视表加载的属性.加载它们是没有问题,但装载,并结合正确的结合WHERE,AND并OR声明是.
以下代码应该为您提供所需的内容,但是您应该注意到您的表目前有一个黄色和蔬菜列表的番茄.显然你想要番茄是红色的而番茄实际上是一种水果而不是蔬菜:
Select distinct title
from products p
inner join
product_variants pv on pv.product_id = p.id
inner join
product_variant_has_properties pvp on pvp.variant_id = pv.id
inner join
product_has_properties php on php.product_id = p.id
inner join
properties ps1 on ps1.id = pvp.property_id --Color
inner join
properties ps2 on ps2.id = php.property_id --Type
inner join
property_keys pk on pk.id = ps1.property_key_id or pk.id = ps2.property_key_id
where ps1.value = 'Red' and ps2.value = 'Vegetable'
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这是SQL小提琴:http://www.sqlfiddle.com/#!9 / 309ad/3/0
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