hyp*_*ack 1 node.js sinon proxyquire
对于下面的代码片段nodejs,我将如何send使用proxyquire和存根该方法sinon,因为它属于文件index.js?我尝试了很多方法,但经常出错.
var emailjs = require("emailjs");
emailjs.server.connect({
user: obj.user,
password: obj.password,
host: obj.host,
port: obj.port,
tls: obj.tls,
ssl: obj.ssl
})
.send(mailOptions, function(error, message){
if (error) {
console.log("ERROR");
context.done(new Error("There was an error sending the email: %s", error));
return;
} else {
console.log("SENT");
context.done();
return;
}
});
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到目前为止,在我的测试中,我有以下设置,但得到Uncaught TypeError: Property 'connect' of object #<Object> is not a function.
readFileStub = sinon.stub();
sendStub = sinon.stub();
connectStub = sinon.stub().returns(sendStub);
testedModule = proxyquire('../index', {
'fs': {readFile: readFileStub},
'emailjs': {
'server': {
'connect': {
'send': sendStub
}
}
}
});
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看起来你几乎就在那里.只需指定connectStub:
readFileStub = sinon.stub();
sendStub = sinon.stub();
connectStub = sinon.stub().returns({
send: sendStub
});
testedModule = proxyquire('../index', {
'fs': {readFile: readFileStub},
'emailjs': {
'server': {
'connect': connectStub
}
}
});
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当connectStub调用它时,它将返回sendStub,然后立即调用它.
编辑:
对,抱歉 - connectStub返回一个对象.
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